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Alla [95]
3 years ago
14

All whole numbers less than or equal to 2​

Mathematics
1 answer:
raketka [301]3 years ago
8 0

Answer: 2,1,0,-1,-2,-3,-4,-5,-5,-6.-7,-8,-9.-10,-11,-12,-13,-14,-15,-16-,17

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I need help with this
gulaghasi [49]
The answer to the question is A
8 0
3 years ago
In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal dist
Marrrta [24]

Answer:

a) Bi [P ( X >=15 ) ] ≈ 0.9944

b) Bi [P ( X >=30 ) ] ≈ 0.3182

c)  Bi [P ( 25=< X =< 35 ) ] ≈ 0.6623

d) Bi [P ( X >40 ) ] ≈ 0.0046  

Step-by-step explanation:

Given:

- Total sample size n = 745

- The probability of success p = 0.037

- The probability of failure q = 0.963

Find:

a. 15 or more will live beyond their 90th birthday

b. 30 or more will live beyond their 90th birthday

c. between 25 and 35 will live beyond their 90th birthday

d. more than 40 will live beyond their 90th birthday

Solution:

- The condition for normal approximation to binomial distribution:                                                

                    n*p = 745*0.037 = 27.565 > 5

                    n*q = 745*0.963 = 717.435 > 5

                    Normal Approximation is valid.

a) P ( X >= 15 ) ?

 - Apply continuity correction for normal approximation:

                Bi [P ( X >=15 ) ] = N [ P ( X >= 14.5 ) ]

 - Then the parameters u mean and σ standard deviation for normal distribution are:

                u = n*p = 27.565

                σ = sqrt ( n*p*q ) = sqrt ( 745*0.037*0.963 ) = 5.1522

- The random variable has approximated normal distribution as follows:

                X~N ( 27.565 , 5.1522^2 )

- Now compute the Z - value for the corrected limit:

                N [ P ( X >= 14.5 ) ] = P ( Z >= (14.5 - 27.565) / 5.1522 )

                N [ P ( X >= 14.5 ) ] = P ( Z >= -2.5358 )

- Now use the Z-score table to evaluate the probability:

                P ( Z >= -2.5358 ) = 0.9944

                N [ P ( X >= 14.5 ) ] = P ( Z >= -2.5358 ) = 0.9944

Hence,

                Bi [P ( X >=15 ) ] ≈ 0.9944

b) P ( X >= 30 ) ?

 - Apply continuity correction for normal approximation:

                Bi [P ( X >=30 ) ] = N [ P ( X >= 29.5 ) ]

- Now compute the Z - value for the corrected limit:

                N [ P ( X >= 29.5 ) ] = P ( Z >= (29.5 - 27.565) / 5.1522 )

                N [ P ( X >= 29.5 ) ] = P ( Z >= 0.37556 )

- Now use the Z-score table to evaluate the probability:

                P ( Z >= 0.37556 ) = 0.3182

                N [ P ( X >= 29.5 ) ] = P ( Z >= 0.37556 ) = 0.3182

Hence,

                Bi [P ( X >=30 ) ] ≈ 0.3182  

c) P ( 25=< X =< 35 ) ?

 - Apply continuity correction for normal approximation:

                Bi [P ( 25=< X =< 35 ) ] = N [ P ( 24.5=< X =< 35.5 ) ]

- Now compute the Z - value for the corrected limit:

                N [ P ( 24.5=< X =< 35.5 ) ]= P ( (24.5 - 27.565) / 5.1522 =<Z =< (35.5 - 27.565) / 5.1522 )

                N [ P ( 24.5=< X =< 25.5 ) ] = P ( -0.59489 =<Z =< 1.54011 )

- Now use the Z-score table to evaluate the probability:

                P ( -0.59489 =<Z =< 1.54011 ) = 0.6623

               N [ P ( 24.5=< X =< 35.5 ) ]= P ( -0.59489 =<Z =< 1.54011 ) = 0.6623

Hence,

                Bi [P ( 25=< X =< 35 ) ] ≈ 0.6623

d) P ( X > 40 ) ?

 - Apply continuity correction for normal approximation:

                Bi [P ( X >40 ) ] = N [ P ( X > 41 ) ]

- Now compute the Z - value for the corrected limit:

                N [ P ( X > 41 ) ] = P ( Z > (41 - 27.565) / 5.1522 )

                N [ P ( X > 41 ) ] = P ( Z > 2.60762 )

- Now use the Z-score table to evaluate the probability:

               P ( Z > 2.60762 ) = 0.0046

               N [ P ( X > 41 ) ] =  P ( Z > 2.60762 ) = 0.0046

Hence,

                Bi [P ( X >40 ) ] ≈ 0.0046  

4 0
3 years ago
Can someone help me please
Taya2010 [7]

Answer:

n = -1

Step-by-step explanation:

n^2 + 5n + 1 = 3n

N^2 +2n +1 = 0       (subtract 3n from both sides)

(n+1)(n+1) = 0   (factor

n+1 =0; n= -1

n+1 = 0  ; n=-1

4 0
2 years ago
Two more than the square of a number is 123 what is the number? Can someone please explain to me how to do this
max2010maxim [7]

Give the number a label.  That can be anything you want.  A lot of people will use 'x' every single time they do a math problem,but there's no reason to do that and it's boring.  Let's call our number ' M ' for 'Mystery number'.  OK ? 

                                             The number . . . M
                       The square of the number . . . M²
Two more than the square of the number . . . M² + 2

You said that this is equal to 123,  so we can write    <u> M² + 2 = 123</u>

That's the equation we have to take and solve for ' M '.

Subtract  2  from each side of the equation, and you have    M² = 121 .

Take the square root of each side:    M = √121 .

The Mystery number is the square root of  121.

If you don't happen to know what that is, then you can use your pocket
calculator, or the calculator that comes with your computer (if you know
how to find it).  They will all tell you that the square root of  121  is  <em>11</em> .

That's a fine and wonderful answer, but technically, it's only half of the
answer.  Any equation that has something squared in it almost always
has two solutions, and this one does.

The square root of  121  is a number that gives you  121  when you
multiply it by itself.  ' 11 ' does that:  (11 x 11) = 121 .  Is there <em><u>another</u></em>
number that does the same thing ?

How about ' -11 ' ?  Look at this:  ( -11 x -11 ) = 121 .  (Remember that
if both numbers being multiplied have the <em>same sign</em>, then their product
is positive.)

The bottom line is:  The mystery number is<em>  +11</em>  and also<em>  -11</em> .
Either one does what you want . . . When you square it and then
add  2  more, you get  123  either way.


6 0
3 years ago
In the cube shown below, the distance between vertices 2 and 6 is 18 cm.
Aleks [24]

Answer:

<h3>C. 54 sq cm</h3>

Step-by-step explanation:

<h3>sana po makatulong</h3>

7 0
3 years ago
Read 2 more answers
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