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soldi70 [24.7K]
3 years ago
9

Complete the following math operations giving the answer with the correct significant digits.

Physics
1 answer:
neonofarm [45]3 years ago
6 0

Answer:

15,000

Explanation:

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You and a friend each carry identical boxes from the first floor of a building to a room located on the second floor, farther do
melamori03 [73]

Answer:

Work done in both the cases will be same

Explanation:

As we know that the work done against gravity is given as

W = F_g .d

here we know that gravitational force is a conservative force and the work done against gravitational force is independent of the path

So here the work done by person to move the object between two different heights will be independent of the path they choose

So for the first person and second person will be same in both the cases because the height through which the boxes are transferred will be same in both the cases

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3 years ago
Suppose a man pushes a crate with a force of 20 N north. What is the magnitude and direction of the reaction force?
Goryan [66]

20 N north because He is pushing it 20 newtons north.

5 0
3 years ago
The chemical name for bleach is sodium hypochlorite (NaClO). It is created by a chemical reaction between sodium (Na), chlorine
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<span>O + Na + Cl = NaClO

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O -> </span><span>Oxygen
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4 0
3 years ago
Read 2 more answers
Which option is part of designing a set of experimental procedures
-BARSIC- [3]

determining how data will he gathered

Explanation: Apex

7 0
3 years ago
Particle q₁ has a charge of 2.7 μC and a velocity of 773 m/s. If it experiences a magnetic force of 5.75 × 10⁻³ N, what is the s
Ne4ueva [31]
The intensity of the magnetic force F experienced by a charge q moving with speed v in a magnetic field of intensity B is equal to
F=qvB \sin \theta
where \theta is the angle between the directions of v and B.

1) Re-arranging the previous formula, we can calculate the value of the magnetic field intensity. The charge is q=2.7 \mu C=2.7 \cdot 10^{-6}C. In this case, v and B are perpendicular, so \theta=90^{\circ}, therefore we have:
B= \frac{F}{qv \sin \theta} = \frac{5.75 \cdot 10^{-3}N}{(2.7 \cdot 10^{-6}C)(773m/s)\sin 90^{\circ}}=2.8 T

2) In this second case, the angle between v and B is \theta=55^{\circ}. The charge is now q=42.0 \mu C=42.0 \cdot 10^{-6}C, and the magnetic field is the one we found in the previous part, B=2.8 T, so we can find the intensity of the force experienced by this second charge:
F=qvB \sin \theta=(42\cdot 10^{-6}C)(1.21 \cdot 10^3 m/s)(2.8 T)(\sin 55^{\circ})=0.12 N
5 0
3 years ago
Read 2 more answers
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