Complete the following math operations giving the answer with the correct significant digits.

Describe the difference between the three states of matter in terms of movement behavior at room temperature and how they intera

yuradex [85]

In solids, the atoms are closely bound to each other. The only movement possible for the atoms in this state of matter is vibration. Solids have a fixed shape. Therefore when they are put in a container, the solids remain in their initial shape.

In liquids, the atoms are loosely bound compared to atoms in solid. And the atoms are free to vibrate and to slide past each other. The liquids have fixed volume but have no fixed shape. Therefore, when they are poured into a container, their volume will be the same, but the liquid will take the shape of the container.

In gas, the atoms are very loosely bound. and the atoms are very free to vibrate and move through space. Gases do not have either fixed volume or a fixed shape. Therefore, when they are poured into a container they take the volume and the shape of the container.

5 0

1 year ago

In a carnival ride, passengers stand with their backs against the wall of a cylinder. The cylinder is set into rotation and the

Lerok [7]

Answer:

Minimum speed will be equal to 2.213 m/sec

Explanation:

We have given radius of the r = 2 m

Coefficient of friction $\mu =0.25$

At minimum speed frictional force will be equal to centripetal force

So $\mu mg=\frac{mv^2}{r}$

$\frac{v^2}{r}=\mu g$

$v=\sqrt{\mu rg}=\sqrt{0.25\times 2\times 9.8}=2.213m/sec$

So the minimum speed will be equal to 2.213 m/sec

8 0

3 years ago

find the mass of a ball on a roof 30 meters high, if the ball's gravitational potential energy is 58.8 joules

Sidana [21]

We are given the gravitational potential energy and the height of the ball and is asked in the problem to determine the mass of the ball. the formula to be followed is PE = mgh where g is the gravitational acceleration equal to 9.81 m/s^2. substituting, 58.8 J = m*9.8 m/s^2 * 30 m; m = 0.2 kg.

3 0

3 years ago

Read 2 more answers

An electron is moving east in a uniform electric field of 1.55 N/C directed to the west. At point A, the velocity of the electro

valkas [14]

Answer:

Final velocity of electron, $v=6.45\times 10^5\ m/s$

Explanation:

It is given that,

Electric field, E = 1.55 N/C

Initial velocity at point A, $u=4.52\times 10^5\ m/s$

We need to find the speed of the electron when it reaches point B which is a distance of 0.395 m east of point A. It can be calculated using third equation of motion as :

$v^2=u^2+2as$ ........(1)