Answer:
1.16kg is the answer. Hope this helped
Explanation:
Answer: Part A the right sentence is: Because the proton is a positive charge and it slows down as it travels, it must be moving from a region of lower potential to a region of higher potential
Part B. aproximatelly 98 times ΔV V
Part C. the initial kinetic energy of the proton is 1.87 10^3 eV
Explanation: Part A. The field stops the proton so the lines of electric fild must be directed in opposite direction of its movement. This means that the proton moves to a higher potential. Part B The kinetic energy of the is transformed in electric potenctial for the proton.
Part C. Energy in J divide the charge of electron gives the energy in eV.
The answer is:
71.6 <span>°F</span>
The problem ask to calculate the bullet's flight time and the bullet's speed as it left the barrel. So base on the problem, the answer would be that the flight time is 0.076 seconds and the speed of the bullet is 657.9 m/s. I hope you are satisfied with my answer and feel free to ask for more if you have questions and further clarifications.
