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DiKsa [7]
2 years ago
10

The acceleration due to gravity on the moon is about 1/6 of the acceleration due to gravity on the earth. A net force F acts hor

izontally on an object on the Moon, producing an acceleration equal to am. In the absence of friction and drag, the same force acting on the same object on Earth would produce an acceleration i.e. equal to
a. 6am
b. (1/6)am
c. am
d. 0
e. 9.8 m/s2
Physics
1 answer:
uysha [10]2 years ago
3 0

Answer:

c.a_m

Explanation:

We are given that

Acceleration due to gravity on the moon=a_m

Acceleration due to gravity on the earth=a_e

g_m=\frac{1}{6}g_e

Net force due to am on an object on moon=F_{net}=ma_m

There is no friction and no drag force and there is no gravity involved

Then, the force acting on an object on earth=F=ma_e

F=F_{net}(given)

ma_m=ma_e

a_e=a_m

Hence, option c is true.

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A +1.0 nC charge is at x = 0 cm, a -1.0 nC charge is at x = 1.0 cm and a 4.0 nC at x= 2 cm. What is the electric potential energ
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Answer:

- 2.7 x 10^-6 J

Explanation:

q1 = 1 nC  at x = 0 cm

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U=\frac{Kq_{1}q_{2}}{r}

where r be the distance between the two charges

By use of superposition principle, the total energy of the system is given by

U = U_{1,2}+U_{2,3}+U_{3,1}

U=\frac{Kq_{1}q_{2}}{0.01}+\frac{Kq_{2}q_{3}}{0.01}+\frac{Kq_{3}q_{1}}{0.02}

U=-\frac{9\times10^{9}\times 1\times10^{-9}\times 1\times10^{-9}}}{0.01}-\frac{9\times10^{9}\times 1\times10^{-9}\times 4\times10^{-9}}}{0.01}+-\frac{9\times10^{9}\times 1\times10^{-9}\times 4\times10^{-9}}}{0.02}

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3 0
3 years ago
What is the KE of a bicycle with a mass of 41kg traveling at a velocity of 8 m/s ?
zhuklara [117]

Answer:

What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s? Physics ... K=12mv2=12×14 kg × (3 m/s)2=63 Joule.

1 answer  

63 Joule Explanation: K=12mv2=12×14 kg × (3 m/s)2=63 Joule

Explanation:

K=12mv2=12×14 kg × (3 m/s)2=63 Joule.

63 Joule Explanation: K=12mv2=12×14 kg × (3 m/s)2=63 Joule

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2 years ago
How much force (in Newtons) acts on a 1700 kg car going around a
Daniel [21]

Answer:

b) 4781 N

Explanation:

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