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V125BC [204]
3 years ago
5

Energy that is stored is called...

Physics
2 answers:
mash [69]3 years ago
7 0
Potential energy

Potential energy is stored energy and the energy of position––gravitational energy. There are several forms of potential energy. Electrical Energy is the movement of electrical charges.
vodomira [7]3 years ago
5 0

Answer:

Potential energy

Explanation:

Potential energy is stored energy and the energy of position––gravitational energy. There are several forms of potential energy. Electrical Energy is the movement of electrical charges. Everything is made of tiny particles called atoms.

- Scientific Forms of Energy_ Stored Energy, Kinetic Energy ...ei.lehigh.edu › learners › energy › readings › energy_basics

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8) c
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The sun is more massive than the moon, but the sun is farther from the earth. Which one exerts a greater gravitational force on
love history [14]

Answer:

178.4 times

Explanation:

We have Newton formula for attraction force between 2 objects with mass and a distance between them:

F_G = G\frac{M_1M_2}{R^2}

where G =6.67408 × 10^{-11} m^3/kgs^2 is the gravitational constant on Earth. M_1, M_2 is the masses of the 2 objects. and R is the distance between them.

From here we can calculate the ratio of gravitational force between the moon and the sun

\frac{F_s}{F_m} = \frac{G\frac{MM_s}{R_s^2}}{G\frac{MM_m}{R_m^2}}

We can divide the top and bottom by G and M

\frac{F_s}{F_m}= \frac{M_s}{R_s^2}:\frac{M_m}{R_m^2}

= \frac{M_s}{R_s^2}\frac{R_m^2}{M_m}

= \frac{M_s}{M_m}(\frac{R_m}{R_s})^2

= \frac{1.99*10^{30}}{7.35*10^{22}}(\frac{3.85*10^8}{1.5*10^{11}})^2

= 27074830*6.59*10^{-6} = 178.4

So the gravitational force of the sun is about 178 times greater than that of the moon to an object on Earth

5 0
3 years ago
After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 54.0 cm. The explorer finds that
Natasha2012 [34]

Answer:

g = 11.2 m/s²

Explanation:

First, we will calculate the time period of the pendulum:

T = \frac{t}{n}

where,

T = Time period = ?

t = time taken = 135 s

n = no. of swings in given time = 98

Therefore,

T = \frac{135\ s}{98}

T = 1.38 s

Now, we utilize the second formula for the time period of the simple pendulum, given as follows:

T = 2\pi \sqrt{\frac{l}{g}}

where,

l = length of pendulum = 54 cm = 0.54 m

g = acceleration due to gravity on the planet = ?

Therefore,

(1.38\ s)^2 = 4\pi^2(\frac{0.54\ m}{g} )\\\\g = \frac{4\pi^2(0.54\ m)}{(1.38\ s)^2}

<u>g = 11.2 m/s²</u>

3 0
3 years ago
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