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yuradex [85]
3 years ago
14

A baseball player leads off the game and hits a long home run. The ball leaves the bat at an angle of 30.0° from the horizontal

with a velocity of 40.0 m/s. How far horizontally will it travel in the air? High high did it go? How long is it in the air?​
Physics
1 answer:
Orlov [11]3 years ago
7 0

it traveled 178.87 m horizontally

it was .041 m high

it was in the air for 4.59 sec

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The White colored star is likely to be the coldest
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What is the slope of the line plotted below? (-2,-1) (4,2) A. 1 B. 2 C. -0.5 D. 0.5
Dmitry [639]

Answer: D. 0.5

Explanation:

The slope formula is y2-y1/x2-x1.

2-(-1)/4-(-2) = 2+1/4+2

2+1/4+2 = 3/6 = 1/2

1/2 = 0.5

The slope is 1/2, or 0.5.

8 0
3 years ago
A solid sphere of radius 40.0 cm has a total positive charge of 16.2 μC uniformly distributed throughout its volume. Calculate t
Jobisdone [24]

Answer:

(a) E=0  :   0 cm from the center of the sphere

(b) E= 227.8*10³ N/C   :    10.0 cm from the center of the sphere

(c)E= 911.25*10³ N/C    :    40.0 cm from the center of the sphere

(d)E= 411.84 * 10³ N/C  :    59.5 cm from the center of the sphere

Explanation:

If we have a uniform charge sphere we can use the following formulas to calculate the Electric field due to the charge of the sphere

E=\frac{K*Q}{r^{2} } : Formula (1) To calculate the electric field in the region outside the sphere r ≥ a

E=k*\frac{Q}{a^{3} } *r :Formula (2) To calculate the electric field in the inner region of the sphere. r ≤ a

Where:

K: coulomb constant

a: sphere radius

Q:  Total sphere charge

r : Distance from the center of the sphere to the region where the electric field is calculated

Equivalences

1μC=10⁻⁶C

1cm= 10⁻²m

Data

k= 9*10⁹ N*m²/C²

Q=16.2 μC=16.2 *10⁻⁶C

a= 40 cm = 40*10⁻²m = 0.4m

Problem development

(a)Magnitude of the electric field at  0 cm :

We replace r=0 in the formula (2) , then, E=0

(b) Magnitude of the electric field at 10.0 cm from the center of the sphere

r<a , We apply the Formula (2):

E=9*10^{9} *\frac{16.2*10^{-6} }{0.4^{3} } *0.1

E= 227.8*10³ N/C

(c) Magnitude of the electric field at 40.0 cm from the center of the sphere

r=a, We apply the Formula (1) :

E=\frac{9*10^{9}*16.2*10^{-6} }{0.4^{2} }

E= 911.25*10³ N/C

(d) Magnitude of the electric field at 59.5 cm from the center of the sphere  

r>a , We apply the Formula (1) :

E=\frac{9*10^{9}*16.2*10^{-6} }{0.595^{2} }

E= 411.84 * 10³ N/C

4 0
3 years ago
What is the wavelength of a wave whose speed and period are 72.0 m/s and 5.00 s , respectively ?
uranmaximum [27]

Answer:

The distance between the two successive crests of the wave is 360m

Explanation:

Wavelength is defined as the property of wave in which the distance between identical points between two successive waves are calculated

Wavelength is referred to as the <em>distance between two successive crests or troughs</em>

<em>Given that:</em>

speed = 72.0 m/s

time = 5 seconds

Using the formula

C = fλ

Where C = speed, f = freequency and λ = wavelength

F = 1 / time

F = 1/5

F = 0.2Hz

From the fomula C = fλ

make λ the subject of the formula

λ = C / f

λ = 72/0.2

<em>λ = 360m</em>

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2 years ago
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The answer would be 4 A.
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