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agasfer [191]
4 years ago
13

If a chemical reaction such as photosynthesis begins with 6 atoms of carbon C , how many atoms of carbon C should be in the prod

ucts?a. 12 atoms of carbon Cb. 6 atoms of carbon Cc. 3 atoms of carbon Cd. 2 atoms of carbon C
Chemistry
1 answer:
lara [203]4 years ago
8 0

Answer:

Option B. 6 atoms of carbon

Explanation:

In <u><em>any chemical reaction</em></u>, atoms from reactant side and product side must be the same.

This is photosynthesis reaction:

6CO₂  + 6H₂O  →  C₆H₁₂O₆  +  6O₂

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elena-s [515]

Answer:

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8 0
3 years ago
Titanium will react with magnesium oxide but sodium reacts with titanium oxide.
yuradex [85]

Answer:

below sodium but above magnesium

Explanation:

It is necessary to note that only a metal that is above another metal in the activity series can displace it from its compound.

The first statement said that titanium reacts with magnesium oxide. The implication of this is that titanium can displace magnesium from its oxide. This is only possible if titanium is above magnesium in the activity series.

The second statement says that sodium reacts with titanium oxide. This implies that sodium metal can displace titanium from its oxide. For this to occur, then sodium must be above titanium in the activity series of metals. Hence the answer above.

5 0
3 years ago
Determine the block of the element Iron which has 26 atomic number:
ziro4ka [17]

Answer:

ok

Explanation:

4 0
3 years ago
Read 2 more answers
What is the mass for 3.01*10 23 molecules h2o
Genrish500 [490]
<em>M H₂O: 1g×2 + 16g = 18g
</em>

6,02×10²³ --------- 18g
3,01×10²³ --------- Xg
X = (18×3,01×10²³)/<span>6,02×10²³
<u>X = 9g

</u>:)
</span>
7 0
4 years ago
Read 2 more answers
Complete and balance the reaction in acidic solution. equation: ZnS + NO_{3}^{-} -&gt; Zn^{2+} + S + NO ZnS+NO−3⟶Zn2++S+NO Which
kotykmax [81]

Answer:

Balanced reaction: 3ZnS+2NO_{3}^{-}+8H^{+}\rightarrow 3Zn^{2+}+3S+2NO+4H_{2}O

S is oxidized and N is reduced.

NO_{3}^{-} is the oxidizing agent and ZnS is the reducing agent.

Explanation:

Reaction: ZnS+NO_{3}^{-}\rightarrow Zn^{2+}+S+NO

\Rightarrow Oxidation: ZnS\rightarrow Zn^{2+}+S

Balance charge: ZnS-2e^{-}\rightarrow Zn^{2+}+S  ...............(1)

\Rightarrow Reduction: NO_{3}^{-}\rightarrow NO

Balance H and O in acidic medium : NO_{3}^{-}+4H^{+}\rightarrow NO+2H_{2}O

Balance charge: NO_{3}^{-}+4H^{+}+3e^{-}\rightarrow NO+2H_{2}O ...............(2)

[3\timesEquation-(1)] + [ 2\timesEquation-(2)]:

3ZnS+2NO_{3}^{-}+8H^{+}\rightarrow 3Zn^{2+}+3S+2NO+4H_{2}O

Oxidation number of S increases from (-2) to (0) for the conversion of ZnS to S. Therefore S is oxidized.

Oxidation number of N decreases from (+5) to (+2) for the conversion of NO_{3}^{-} to NO. Therefore N is reduced.

NO_{3}^{-} consumes electron from ZnS. Therefore NO_{3}^{-} is the oxidizing agent and ZnS is the reducing agent.

7 0
3 years ago
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