Answer:
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The balance equation for the reaction between sodium bicarbonate and hydrochloric acid:
![NaHCO_3_(_s_) + HCl_(_a_q_) \implies NaCl_(_a_q_) + CO_2_(_g_) + H_2O_(_l_)](https://tex.z-dn.net/?f=NaHCO_3_%28_s_%29%20%2B%20HCl_%28_a_q_%29%20%5Cimplies%20NaCl_%28_a_q_%29%20%2B%20CO_2_%28_g_%29%20%2B%20H_2O_%28_l_%29)
The reactants
and
react in the ratio 1:1. So we use the mass of sodium bicarbonate and molar mass to find the number of moles produced.
.
.
Again we use the fact that the stochiometric ratio are 1:1:1:1:1, hence the moles of
are 24.977moles.
So we used the ideal gas law
, where P is the pressure, V is the volume, R the gas constant, is
and T is the temperature in kelvins. We make V the subject
![PV= nRT \implies V= \frac{nRT}{P}= \frac{ 24.997\ mol \times 8.2507m^3\ atm \times 298.15K }{mol \times K \times 1.23 atm} = 49967\ m^3](https://tex.z-dn.net/?f=PV%3D%20nRT%20%5Cimplies%20V%3D%20%5Cfrac%7BnRT%7D%7BP%7D%3D%20%5Cfrac%7B%2024.997%5C%20mol%20%5Ctimes%208.2507m%5E3%5C%20atm%20%5Ctimes%20298.15K%20%7D%7Bmol%20%5Ctimes%20K%20%5Ctimes%201.23%20atm%7D%20%3D%2049967%5C%20m%5E3)
The answer is supposed to be in L,
, so
![49967\ m^3 \times\frac{L}{1000\ m^3} =49.97L\ CO_2\ produced](https://tex.z-dn.net/?f=49967%5C%20m%5E3%20%5Ctimes%5Cfrac%7BL%7D%7B1000%5C%20m%5E3%7D%20%3D49.97L%5C%20CO_2%5C%20produced)
Answer:
a.
can be made up of a combination of different elements.
Answer: Because acetic acid in solution exists as a mixture of acetic acid & dissociated acetic acid (acetate)
Hope this helps!