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3 years ago

Pancake syrup is an example of a

Physics

1 answer:

laila [671]3 years ago

8 0

It is an example of liquid. if thats what you are asking for...

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how could the specific heat of the substance your container will hold affect the performance of the container?

ratelena [41]

Answer:

I am not entirely sure, but I hope this helps ;)

Heat transfers from a very hot body always, and into a colder body. This is due to the change in temperatures at which the two bodies exist, and also it depends upon its magnitude. And, the heat exchange stop once both the bodies attain same temperature.

And from the relation of heat equation, we get that it is directly proportionate to the substance's specific heat. But, there is no such thing that the area of contact is important, for heat transfer. It gets transferred although a small point is in contact.

4 0

3 years ago

When balls roll out of sight, do they disappear or play hopscotch? Or maybe……. Just maybe…… they play hide and seek. I’m not rea

Anuta_ua [19.1K]

Answer:

they play hide and seek with me and im always the seeker U-U

Explanation:

3 0

3 years ago

Find a numerical value for rhoearth, the average density of the earth in kilograms per cubic meter. Use 6378km for the radius of

mylen [45]

Answer:

density = 5520 kg/m^3

Explanation:

given that

radius of earth = 6378 km

G = 6.67 x 10⁻¹¹ m³/kg.s²

g = 9.80 m/s²

we know,

$g = \dfrac{GM}{r^2}$

mass of earth

$M = \dfrac{gr^2}{G}$

$M = \dfrac{9.8 \times (6378 \times 10^3)^2}{6.67 \times 10^{-11}}$

M = 5.972 x 10²⁴ kg

density = $\dfrac{mass}{volume}$

V = volume of the earth = 4/3πr³

V = 4/3 x 3.14 x (6378 x 10³)³

V = 1.08 x 10²¹ m³

density = $\dfrac{5.972\times 10^{24}}{1.08\times 10^{21}}$

density = 5.52 x 10³ kg/m^3

density = 5520 kg/m^3

8 0

3 years ago

1. Una carga eléctrica de 5*10-6 C genera un campo eléctrico a su alrededor. Calcula la intensidad de este campo a una distancia

Jlenok [28]

Answer:

La intensidad del campo eléctrico es 70312.5 $\frac{N}{C}$ .

Explanation:

La perturbación que crea en torno a ella una carga eléctrica se representa mediante un vector denominado campo eléctrico.

Se dice que un campo eléctrico es uniforme en una región del espacio cuando la intensidad de dicho campo eléctrico es el mismo en todos los puntos de dicha región.

El campo eléctrico E creado por la carga puntual q en un punto cualquiera P se define como:

$E=k*\frac{q}{r^{2} }$

donde q es la carga creadora del campo, k es la constante electrostática y r es la distancia desde la carga fuente al punto P.

En este caso, los datos son:

k= 9*10⁹ $\frac{N*m^{2} }{C^{2} }$
q= 5*10⁻⁶ C
r= 0.8 m

Reemplazando:

$E=9*10^{9}\frac{N*m^{2} }{C^{2} } *\frac{5*10^{-6} C}{(0.8 m)^{2} }$

Resolviendo:

E= 70312.5 $\frac{N}{C}$

La intensidad del campo eléctrico es 70312.5 $\frac{N}{C}$ .

5 0

3 years ago

Which of the following describes volume?

kolezko [41]

The option that describes volume is B. the amount of space that matter occupies.
It refers to the area within which some body is contained, and is usually measured in cubic meters, or any variation of the meter.

5 0

3 years ago