Answer:
0.54 mole of H2O.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2CH3OH + 3O2 —> 2CO2 + 4H2O
From the balanced equation above,
2 moles of CH3OH reacted to produce 4 moles of water.
Finally, we shall determine the number of mole of water (H2O) produced by the reaction of 0.27 moles of CH3OH. This can be obtained as follow:
From the balanced equation above,
2 moles of CH3OH reacted to produce 4 moles of water.
Therefore, 0.27 moles of CH3OH will react to produce = (0.27 × 4)/2 = 0.54 mole of H2O.
Thus, 0.54 mole of H2O is produced from the reaction.
Sulfur and sodium are those two elements
Answer:
The answer to your question is HCl + NaOH ⇒ NaCl + H₂O
Explanation:
Data
Double displacement reaction
Balanced chemical reaction
HCl + NaOH ⇒ NaCl + H₂O
Reactants Elements Products
1 Chlorine (Cl) 1
1 Sodium (Na) 1
2 Hydrogen (H) 2
1 Oxygen (0) 1
As we can see, the reaction is balanced and the coefficients of all reactants and products are 1, but the number is not written in a balanced reaction.
C)"his refusal to cooperate with the police and name the culprit...resulted in his arrest..."
D. this is the correct answer because the question is showing a comparison of sizes rather than the actual sizes which eliminates B. A and C have no relevance.
