The radius of the sphere in meters is ,r = 
Think about the angle the ground and the shadow make. Since the sun's beams are parallel, the angle created by the stick's shadow is also equal. Since the stick is 1 m high and its shadow is 2 m long, we know that the stick's angle is arctan 1/2. Therefore, by thinking of a right-angled triangle,
r/10 = tan [arctan(1/2)] = tan (1/2)
Since, tan (θ/2) = 1-cos(θ) / sin(θ)
we find that,
r/10 = 
Hence, r =
So, the radius of the sphere in meters is ,r =
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Energy cannot be created nor be destroyed
Hey there!
In this case, it is possible to solve this problem by using the widely-known steam tables which show that at 90 °C, the pressure that produces a vapor-liquid mixture at equilibrium is about 70.183 kPa (Cengel, Thermodynamics 5th edition).
Moreover, for the calculation of the volume, it is necessary to calculate the volume of the vapor-liquid mixture, given the quality (x) it has:
Thus, since 8 kg correspond to liquid water, 2 kg must correspond to steam, so that the quality turns out:
Now, at this temperature and pressure, the volume of a saturated vapor is 2.3593 m³/kg whereas that of the saturated liquid is 0.001036 m³/kg and therefore, the volume of the mixture is:
This means that the volume of the container will be:
Regards!
Answer:
429 m
Explanation:
In this exercise you are suppose to simulate a right triangle, the catheti are the distance you walked and the height of the empire state building.
tan(88) = (height) /(distance you walked)
28.64 = height / 15
height = 429 m
