1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
erica [24]
3 years ago
9

True or False? An airplane is flying West at 200 kilometers per hour 2 hours later it is flying West at 300 km/h its average acc

eleration is 100 kilometers per hour.
Physics
1 answer:
aleksandr82 [10.1K]3 years ago
8 0

False The airplane had an increase of 100kph over a 2 hour period. 100 / 2 = 50. so that would be 50 kph average acceleration.
You might be interested in
1) What do (x) and (y) symbolize?
MArishka [77]

Answer:

x is vertical and y is horizontal

Explanation:

7 0
3 years ago
A circular loop of wire with a radius of 15.0 cm and oriented in the horizontal xy-plane is located in a region of uniform magne
kati45 [8]

Answer:

The average emf that will be induced in the wire loop during the extraction process is 37.9 V

Explanation:

The average emf induced can be calculated from the formula

Emf = -N\frac{\Delta \phi}{\Delta t}

Where N is the number of turns

\Delta \phi is the change in magnetic  flux

\Delta t is the time interval

The change in magnetic flux is given by

\Delta \phi = \phi _{f} - \phi _{i}

Where \phi _{f} is the final magnetic flux

and \phi _{i} is the initial magnetic flux

Magnetic flux is given by the formula

\phi = BAcos(\theta)

Where B is the magnetic field

A is the area

and \theta is the angle between the magnetic field and the area.

Initially, the magnetic field and the area are pointed in the same direction, that is, \theta = 0^{o}

From the question,

B = 1.5 T

and radius = 15.0 cm = 0.15 m

Since it is a circular loop of wire, the area is given by

A = \pi r^{2}

∴ A = \pi (0.15)^{2}

A = 0.0225\pi

∴\phi_{i}  = (1.5)(0.0225\pi)cos(0^{o} )

\phi_{i}  = (1.5)(0.0225\pi)

( NOTE: cos (0^{o}) = 1 )

\phi_{i}  = 0.03375\pi Wb

For \phi_{f}

The field pointed upwards, that is \theta = 90^{o}. Since cos (90^{o}) = 0

Then

\phi_{f} = 0

Hence,

\Delta \phi = 0- 0.03375\pi

\Delta \phi = - 0.03375\pi

From the question

\Delta t = 2.8 ms = 2.8 \times 10^{-3} s

Here, N = 1

Hence,

Emf = -N\frac{\Delta \phi}{\Delta t} becomes

Emf = -(1)\frac{-0.03375\pi}{2.8 \times 10^{-3} }

Emf = 37.9 V

Hence, the average emf that will be induced in the wire loop during the extraction process is 37.9 V.

5 0
3 years ago
What is the particles instantaneous speed at t=16 sec
Ira Lisetskai [31]

It's  3.6 meters per second less than my speed was
at 4:19 PM last Tuesday.

Does that tell you anything ?
Why not ?

 
8 0
3 years ago
The escape velocity at the surface of Earth is approximately 11 km/s. What is the mass, in units of ME (the mass of the Earth),
SVETLANKA909090 [29]

Answer:11 km/s

Explanation:

Given

Escape velocity at the surface of earth is 11 km/s

Escape velocity is given by

V_e=\sqrt{\frac{2GM}{R}}

Escape velocity at the surface of earth

11=\sqrt{\frac{2GM}{R}}--------------------1

If Escape velocity is three times and the radius is also the three times

V_e_2=\sqrt{\frac{2G(3M)}{3R}}

V_e_2=\sqrt{\frac{2GM}{R}}=V_e

i.e. V_e_2=11 km/s

5 0
3 years ago
g The international space station has an orbital period of 93 minutes at an altitude (above Earth's surface) of 410 km. A geosyn
krok68 [10]

Answer:

r = 4.21 10⁷ m

Explanation:

Kepler's third law It is an application of Newton's second law where the forces of the gravitational force, obtaining

            T² = (\frac{4\pi }{G M_s} ) r³             (1)

           

in this case the period of the season is

            T₁ = 93 min (60 s / 1 min) = 5580 s

            r₁ = 410 + 6370 = 6780 km

            r₁ = 6.780 10⁶ m

for the satellite

           T₂ = 24 h (3600 s / 1h) = 86 400 s

if we substitute in equation 1

            T² = K r³

            K = T₁²/r₁³

            K = \frac{ 5580^2}{ (6.780 10^6)^2}

            K = 9.99 10⁻¹⁴ s² / m³

we can replace the satellite values

            r³ = T² / K

            r³ = 86400² / 9.99 10⁻¹⁴

            r = ∛(7.4724 10²²)

            r = 4.21 10⁷ m

this distance is from the center of the earth

7 0
3 years ago
Other questions:
  • A cliff jumper runs off a 15 m high cliff. Rocks extend 3.0 m past the cliff bottom. We can ignore air resistance.What is the mi
    14·1 answer
  • A rock is thrown straight upward off the edge of a balcony that is 5 m above the ground. The rock rises 10 m, then falls all the
    7·1 answer
  • Apr 22, 1:11:18 PM
    8·2 answers
  • Which of these best describes how an appropriate star chart is selected to locate objects in the sky
    10·1 answer
  • What is the net force? <br><br> URGENT! thank you
    8·1 answer
  • Find the speed for a star in which this line appears at wavelength 120.2 nm . Express your answer to three significant figures a
    15·1 answer
  • 1. Using the data from M7:<br>Which four countries are the worst in releasing CO2?​
    15·1 answer
  • In what unit do we measure the work done by a force
    9·1 answer
  • Why? I need some help I would like at least 1 answer <br><br><br> Thanks,<br> Vishnu
    10·1 answer
  • If a lever has a mechanical advantage of 5 and 50 N of force is used to lift a rock, what is the weight of the rock?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!