For Ar :
1 mol ------------ 22.4 L ( at STP )
7.6 mol ---------- x L
x = 7.6 * 22.4
x = 170.24 L
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For C2H3:
1 mol ------------ 22.4 ( at STP)
0.44 mol --------- y L
y = 0.44 * 22.4
y = 9.856 L
hope this helps !.
Answer:
Hydrogen = 2.5 * 10^21
Explanation:
Chemical Formula Glucose: C₆H₁₂O₆
One of the ways you could do this is to notice that for every carbon atom there are two Hydrogen atoms. You can state this more formally by using the formula to set up a ratio: 12/6 = hydrogen to Carbon
So if there are 1.250 * 10^21 Carbon atoms in the Glucose sample, then there will be twice as many hydrogen atoms.
H = 2 * 1.25 * 10^21 = 2.5 * 10^21 atoms
You could do this more formally by setting up a proportion.
6 Carbon / 12 Hydrogen = 1.25*10^21 / x Cross Multiply
6*x = 12 * 1.25*10^21 Combine the right
6x = 1.5 * 10^22 Divide by 6
x = 2.5 * 10^21
Water would have a much lower boiling point much like its other hydrides and it would loss its ability to dissolve polar substances plus it couldn't form water columns so no more cohesion between water molecules
