<em>Answer</em><em>:</em><em>2</em><em>7</em><em>%</em><em> </em><em>According</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>cylinder</em><em>.</em>
The number of moles of C present in C₅H₁₂ that contains 22.5 g of H is 9.375 moles
<h3>How to determine the mass of C₅H₁₂ that contains 22.5 g of H</h3>
1 mole of C₅H₁₂ = (12×5) + (1×12) = 72 g
Mass of H in 1 mole of C₅H₁₂ = 12 × 1 = 12 g
Thus,
12 g of H is present in 72 g of C₅H₁₂
Therefore,
22.5 g of H will be present in = (22.5 × 72) / 12 = 135 g of C₅H₁₂
<h3>How to determine the mole of C present in 135 g of C₅H₁₂</h3>
72 g of C₅H₁₂ contains 5 moles of C
Therefore,
135 g of C₅H₁₂ will contain = (135 × 5) / 72 = 9.375 moles of C
Thus, 9.375 moles of C is present in C₅H₁₂ that contains 22.5 g of H
Learn more about mole:
brainly.com/question/13314627
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Answer:
I think that Gravity is not considered a gas but it can at the same time
Explanation:
Gasses are affected by gravity, as above video will prove. ... Yes, there is a attractive force between the gas molecules and gravity !
The rest are for sure gases
CH4+ 2O2---> CO2+ 2H2O I believe would be correct.
