There are two types of rocks that make up the continental crust "sedimentary and metamorphic rocks." Sedimentary rocks are formed with pressure and compaction, and metamorphic rocks are made with heat and pressure. The earth's crust itself is made up of sedimentary rocks because they are mainly found a little under earths crust same goes with metamorphic rocks.
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Answer:
88.50 %
The balance chemical equation is as follow,
2 H₂ + O₂ → 2 H₂O
Step 1: Find the limiting reactant;
According to eq.
4.032 g (2 mole) H₂ reacts with = 32 g (1 mole) of O₂
So,
11 g of H₂ will react with = X g of O₂
Solving for X,
X = (11 g × 32 g) ÷ 4.032 g
X = 87.301 g of O₂
Therefore, H₂ is the limiting reactant as O₂ is present in excess.
Step 2: Calculating %age Yield;
According to eq.
4.032 g (2 mole) H₂ produces = 36.032 g (1 mole) of H₂O
So,
11 g of H₂ will react with = X g of H₂O
Solving for X,
X = (11 g × 36.032 g) ÷ 4.032 g
X = 98.301 g of H₂O
So,
Actual Yield = 87 g
Theoretical Yield = 98.301 g
Using formula = Actual Yield / Theoretical Yield × 100
= 87 g / 98.301 × 100
= 88.50 %
The question in English is "<span>Determine the mass, in kg, of a material that is contained in a volume of 18L. It is known that the material density is 0.9 g/cm 3"
Answer:
</span>
We can use a simple
equation to solve this problem. <span>
d =
m/v</span><span>
<span>Where </span>d <span>is
the density, </span>m <span>is
the mass and </span>v is the volume.
d = </span>0.9<span> g/cm³
m = ?
v = </span>18 L = 18 x 10³ cm³<span>
By applying the equation,
<span> 0.9 g/cm³ = m / </span></span>18 x 10³ cm³<span>
m = 0.9 g/cm³ x </span>18 x 10³ cm³<span>
<span>
</span>m = 16200 g
m = 16.2 kg
Hence, the mass of
18 L of material is 16.2 kg.</span>
Answer:
on the successful completion of a number of different steps: planning (identifying the most appropriate analytical procedure), sample selection, sample preparation, performance of analytical procedure, statistical analysis
Explanation:
hope it helps
What is in my calculator should be the answer u might have to round to the nearest tenths place
