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solniwko [45]
3 years ago
12

1. A light bulb is filled with 3.54 g of argon at 25 C and 725 mmHg. What is

Chemistry
1 answer:
Ugo [173]3 years ago
3 0

Answer: The volume of given gas is 2.27 L.

Explanation:

Given: Mass = 3.54 g

Temperature = 25^{o}C = (25 + 273) K = 298 K

Pressure = 725 mm Hg (1 mm Hg = 0.00131579) = 0.95 atm

As moles is the mass of substance divided by its molar mass.

So, moles of argon (molar mass = 40 g/mol) is as follows.

Moles = \frac{mass}{molar mass}\\= \frac{3.54 g}{40 g/mol}\\= 0.0885 mol

Formula used to calculate the volume of given gas is as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

PV = nRT\\0.95 atm \times V = 0.0885 mol \times 0.0821 L atm/mol K \times 298 K\\V = 2.27 L

Thus, we can conclude that the volume of given gas is 2.27 L.

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Answer: 9.91×10²³ particles

Explanation:

To find the amount of particles, you will need to use the Ideal Gas Law with what we are given.

Ideal Gas Law: PV=nRT

After we find moles, we can use Avogadro's number to convert to particles.

n=\frac{PV}{RT}

P=101.3kPa=1.00 atm

V=4.0 L

T=23°C+273.15=296.15 K

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n=\frac{(1.00 atm)(4.0 L)}{(0.08206Latm/Kmol)(296.15K)}

n=0.164595 mol

Now that we have moles, we can convert to particles.

0.164595mol*\frac{6.022*10^2^3 particles}{mol} =9.91*10^2^2 particles

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