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FromTheMoon [43]
3 years ago
12

A compound contains only carbon, hydrogen, and oxygen. Combustion of 10.68mg of the compound yields 16.01 mg CO2 and 4.37 mg H2O

. The molar mass of the compound is 176.1g/mol. What are the empirical and molecular formulas?
Chemistry
1 answer:
Zielflug [23.3K]3 years ago
6 0
<span>Molecular formulas tell you how many atoms of each element are in a compound, and empirical formulastell you the simplest or most reduced ratio of elements in a compound. ... Also, many compounds with different molecular formula have the same<span>empirical formula</span></span>
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Define what natural gas is, explain how it forms, and<br> what it is used for today.
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Question 5 (1 point)
ollegr [7]

Answer:

0.00125 moles H₃X

Solution and Explanation:

In this question we are required to calculate the number of moles of triprotic acid neutralized in the titration.

Volume of NaOH used = final burette reading - initial burette reading

                                      = 39.18 ml - 3.19 ml

                                      = 35.99 ml or 0.03599 L

Step 1: Moles of NaOH used

Number of moles = Molarity × Volume

Molarity of NaOH = 0.1041 M

Moles of NaOH = 0.1041 M × 0.03599 L

                          = 0.00375 mole

Step 2: Balanced equation for the reaction between triprotic acid and NaOH

The balanced equation is;

H₃X(aq) + 3NaOH(aq) → Na₃X(aq) + 3H₂O(l)

Step 3: Moles of the triprotic acid (H₃X used

From the balanced equation;

1 mole of the triprotic acid reacts with 3 moles of NaOH

Therefore; the mole ratio of H₃X to NaOH is 1 : 3.

Therefore;

Moles of Triprotic acid = 0.00375 mole ÷ 3

                                     = 0.00125 moles

Hence, moles of triprotic acid neutralized during the titration is 0.00125 moles.

3 0
4 years ago
The nonprescription pain relievers Advil and Nuprin contain ibuprofen (C13H18O2), whose molecular mass is 206.3 amu. If all tabl
brilliants [131]

Answer:

16.92 g C13H18O2

Explanation:

If the molecular mass of C13H18O2 is 206.3 amu, then molar mass of C13H18O2 is 206. 3 g/mol.

So, if we have 0.082 mol C13H18O2, than it is

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