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FromTheMoon [43]
3 years ago
12

A compound contains only carbon, hydrogen, and oxygen. Combustion of 10.68mg of the compound yields 16.01 mg CO2 and 4.37 mg H2O

. The molar mass of the compound is 176.1g/mol. What are the empirical and molecular formulas?
Chemistry
1 answer:
Zielflug [23.3K]3 years ago
6 0
<span>Molecular formulas tell you how many atoms of each element are in a compound, and empirical formulastell you the simplest or most reduced ratio of elements in a compound. ... Also, many compounds with different molecular formula have the same<span>empirical formula</span></span>
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A piece of gold jewelry weighs 11.54 g and has a volume of 0.675 cm3. The jewelry contains only gold (density = 19.3 g/cm3) and
lbvjy [14]

Answer:

Percentage of gold = 84.6%

Explanation:

Suppose the jewelry has x g of gold and y g of silver

The mass of both is the total mass of the jewelry then:

x + y = 11.54

And as the problem says the total volume is the sum of both volumes.

volume = mass / density

\frac{x}{19.3} + \frac{y}{10.5} = 0.675

Solving the system you get:

x = 9.764 g

y = 1.776 g

The percentage of gold in the jewelry is:

X_{gold} = \frac{9.764}{11.54} * 100 = 84.6\%

4 0
2 years ago
What is the energy change when 78.0 g of Hg melt at −38.8°C
adell [148]

Answer:

The correct answer is - 2.557 KJ

Explanation:

In this case, Hg is melting, the process is endothermic, so the energy change will have a positive sign.

we can calculate this energy by the following formula:

Q = met

where, m = mass,

e = specific heat

t = temperature

then,

Q = 78*0.14* (273-38.8)

here 0.14 = C(Hg)

= 2.557 Kj

5 0
2 years ago
Calculate the specific volume of Helium using the compressibility factor. 500 kPa, 60 degrees Celsius
IrinaK [193]

Explanation:

Formula for compressibility factor is as follows.

                     z = \frac{P \times V_{m}}{R \times T}

where,     z = compressibility factor for helium = 1.0005

               P = pressure

          V_{m} = molar volume

                R = gas constant = 8.31 J/mol.K

                T = temperature

So, calculate the molar volume as follows.

                V_{m} = \frac{z \times R \times T}{P}

                             = \frac{1.0005 \times 8.314 \times 10^{-3} m^{3}.kPa/mol K \times (60 + 273)K}{500 kPa}

                             = 0.0056 m^{3}/mol

As molar mass of helium is 4 g/mol. Hence, calculate specific volume of helium as follows.

                    V_{sp} = \frac{V_{m}}{M_{w}}

                           = \frac{0.0056 m^{3}/mol}{4 g/mol}

                           = 0.00139 m^{3}/g

                           = 0.00139 m^{3}/g \times \frac{1 g}{10^{-3}kg}

                                 = 1.39 m^{3}/kg

Thus, we can conclude that the specific volume of Helium in given conditions is 1.39 m^{3}/kg.

7 0
3 years ago
Which of the following elements would be classified as a nonmetal? sulfur aluminum silicon calcium
Ahat [919]
Sulfur is a non metal 
7 0
3 years ago
Read 2 more answers
Please Help!!<br> Qns 1b to 3
Gelneren [198K]

Answer: Ammonium, when heated with aqueous base, will give off NH3 (ammonia) gas, (and depending, water vapor). This will leave the Cr2O3(s). From then on,

it is just adding or subtraction of gases or water vapor. You probably heard “Loss of electrons is Oxidation”, “Gain of Electrons is reduction”. That should help.

Explanation: This isn’t an explanation but an interesting point; Acid-Base and RedOx reactions are useful to the most complex of any Chemistry. Get this down, and Organic Chemistry will be much easier.

7 0
3 years ago
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