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zimovet [89]
3 years ago
15

You and your friends are having a race, but since you are faster than he is, you decide to give him a head start. He starts 10 m

In front if the starting line, while you start on the starting line. You run at 6 meters/ second, while your friend runs at 5.5 meters/ second. After how many seconds will you and your friend be same distance from the starting line?
Mathematics
1 answer:
Vlad1618 [11]3 years ago
3 0

Answer:

the number of seconds that you and your friend would be have the similar distance from the starting line is 20 seconds

Step-by-step explanation:

The computation of the number of seconds that you and your friend would be have the similar distance from the starting line is shown below:

As we know that

Speed = Distance ÷ Time

SO,

Time = Distance ÷ speed

= 10 meters ÷ difference in speed

= 10 meters ÷ (6 meters per second - 5.5 meters per second)

= 10 meters ÷ 0.5 meters per second

= 20 seconds

hence, the number of seconds that you and your friend would be have the similar distance from the starting line is 20 seconds

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What is the value of the expression below?<br><br> 1 3/4 divided by 1/2 minus (1 1/2)^3
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Answer:

1/8

Step-by-step explanation:

Simplify the following:

(1 + 3/4)/(1/2) - (1/2 + 1)^3

Hint: | Write (1 + 3/4)/(1/2) as a single fraction.

Multiply the numerator of (1 + 3/4)/(1/2) by the reciprocal of the denominator. (1 + 3/4)/(1/2) = ((1 + 3/4)×2)/1:

(3/4 + 1) 2 - (1/2 + 1)^3

Hint: | Put the fractions in 1 + 1/2 over a common denominator.

Put 1 + 1/2 over the common denominator 2. 1 + 1/2 = 2/2 + 1/2:

(1 + 3/4) 2 - (2/2 + 1/2)^3

Hint: | Add the fractions over a common denominator to a single fraction.

2/2 + 1/2 = (2 + 1)/2:

(1 + 3/4) 2 - ((2 + 1)/2)^3

Hint: | Evaluate 2 + 1.

2 + 1 = 3:

(1 + 3/4) 2 - (3/2)^3

Hint: | Put the fractions in 1 + 3/4 over a common denominator.

Put 1 + 3/4 over the common denominator 4. 1 + 3/4 = 4/4 + 3/4:

4/4 + 3/4 2 - (3/2)^3

Hint: | Add the fractions over a common denominator to a single fraction.

4/4 + 3/4 = (4 + 3)/4:

(4 + 3)/4×2 - (3/2)^3

Hint: | Evaluate 4 + 3.

4 + 3 = 7:

7/4×2 - (3/2)^3

Hint: | Express 7/4×2 as a single fraction.

7/4×2 = (7×2)/4:

(7×2)/4 - (3/2)^3

Hint: | In (7×2)/4, divide 4 in the denominator by 2 in the numerator.

2/4 = 2/(2×2) = 1/2:

7/2 - (3/2)^3

Hint: | Simplify (3/2)^3 using the rule (p/q)^n = p^n/q^n.

(3/2)^3 = 3^3/2^3:

7/2 - 3^3/2^3

Hint: | In order to evaluate 3^3 express 3^3 as 3×3^2.

3^3 = 3×3^2:

7/2 - (3×3^2)/2^3

Hint: | In order to evaluate 2^3 express 2^3 as 2×2^2.

2^3 = 2×2^2:

7/2 - (3×3^2)/(2×2^2)

Hint: | Evaluate 2^2.

2^2 = 4:

7/2 - (3×3^2)/(2×4)

Hint: | Evaluate 3^2.

3^2 = 9:

7/2 - (3×9)/(2×4)

Hint: | Multiply 2 and 4 together.

2×4 = 8:

7/2 - (3×9)/8

Hint: | Multiply 3 and 9 together.

3×9 = 27:

7/2 - 27/8

Hint: | Put the fractions in 7/2 - 27/8 over a common denominator.

Put 7/2 - 27/8 over the common denominator 8. 7/2 - 27/8 = (4×7)/8 - 27/8:

(4×7)/8 - 27/8

Hint: | Multiply 4 and 7 together.

4×7 = 28:

28/8 - 27/8

Hint: | Subtract the fractions over a common denominator to a single fraction.

28/8 - 27/8 = (28 - 27)/8:

(28 - 27)/8

Hint: | Subtract 27 from 28.

| 2 | 8

- | 2 | 7

| 0 | 1:

Answer: 1/8

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