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kiruha [24]
3 years ago
12

The mass of 150cm³ of stone is 400g. its density is​

Physics
1 answer:
WITCHER [35]3 years ago
3 0

Answer:2.67kgm/s cube

Explanation: density = mass ÷ volume = 400 ÷ 150

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A hummingbird flies forward and backward. Its motion is shown on the above graph of horizontal Position and
harina [27]

Answer:

The hummingbird travels the total distance is 10 m

Explanation:

Given that,

A hummingbird flies forward and backward.

According to figure,

We know that,

The total distance is equal to the sum of all distance.

Forward direction is positive and backward direction is negative.

We need to calculate  the hummingbird travels the total distance

Using figure,

D=d_{1}+d_{2}+d_{3}+d_{4}

Put the value into the formula

D=6+(-4)+2+6

D=10\ m

Hence, The hummingbird travels the total distance is 10 m.

8 0
3 years ago
Physicists often measure the momentum of subatomic particles moving near the speed of light in units of MeV/c, where c is the sp
maxonik [38]

Answer:

kg m/s

Explanation:

e = Charge = C

V = Voltage = \dfrac{N}{C}m

c = Speed of light = m/s

Momentum is given by

\dfrac{MeV}{c}=\dfrac{e\times V}{c}\\\Rightarrow \dfrac{MeV}{c}=\dfrac{C\times \dfrac{N}{C}\times m}{m/s}\\\Rightarrow \dfrac{MeV}{c}=Ns\\\Rightarrow \dfrac{MeV}{c}=kg\times \dfrac{m}{s}\times s\\\Rightarrow \dfrac{MeV}{c}=kg\cdot m/s

The unit of MeV/c in SI fundamental units is kg m/s

5 0
3 years ago
A mid-ocean ridge under the ocean is MOST similar to a _____ on land.
Alexxx [7]
A mid ocean ridge is a under water mountain range, knowing this what would you say it is most similar to on land? hope this helped!
5 0
2 years ago
A cord of mass 0.65 kg is stretched between two supports 28 m apart. if the tension in the cord is 150 n, 2 how long will it tak
MaRussiya [10]
Ans: Time <span>taken by a pulse to travel from one support to the other = 0.348s
</span>
Explanation:
First you need to find out the speed of the wave.

Since
Speed = v = \sqrt{ \frac{T}{\mu} }

Where
T = Tension in the cord = 150N
μ = Mass per unit length = mass/Length = 0.65/28 = 0.0232 kg/m

So
v = \sqrt{ \frac{150}{0.0232} } = 80.41 m/s

Now the time-taken by the wave = t = Length/speed = 28/80.41=0.348s
5 0
3 years ago
A truck driving east on a highway goes from the 42 mi marker to the 48 mi
Leona [35]

Average velocity is 1..2 mi/min east

Explanation:

  • Velocity = Displacement/Time

Here, displacement = 48 mi - 42 mi = 6 miles

Time = 5 minutes

⇒ Average Velocity = 6/5 = 1.2 mi/min east

3 0
3 years ago
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