Answer:
a) 520m
b) 10.30 s
c) 100,95 m/s
Explanation:
a) According the given information, the rocket suddenly stops when it reach the height of 520m, because the engines fail, and then it begins the free fall.
This means the maximum height this rocket reached before falling was 520 m.
b) As we are dealing with constant acceleration (due gravity) 
we can use the following formula:
(1)
Where:
is the initial height of the rocket (at the exact moment in which it stops due engines fail)
is the final height of the rocket (when it finally hits the launch pad)
is the initial velocity of the rocket (at the exact moment in which it stops the velocity is zero and then it begins to fall)
is the acceleration due gravity
is the time it takes to the rocket to hit the launch pad
Clearing :
(2)
(3)
(4)
(5) This is the time
c) Now we need to find the final velocity 
for this rocket, and the following equation will be perfect to find it:
(6)
(7)
(8) This is the final velocity of the rocket. Note the negative sign indicates its direction is downwards (to the launch pad)
Answer:
Explanation:
Given that,
A vector A has x component to be 2.7cm and y component to be 2.25cm
Then,
A = 2.7•i + 2.25•j
A vector B has x component of 0.30cm and y component of 1.75cm
B = 0.3•i + 1.75•j
So, we want to find A+B
Addition of vectors
Generally
(a•i + b•j) + (c•i + d•j) = (a+c)•i +(b+d)•j
Vectors are added component wise.
So,
A + B = (2.7•i + 2.25•j) + (0.3•i + 1.75•j)
A + B = (2.7 + 0.3)•i + (2.25 + 1.75)•j
A + B = 3•i + 4•j
We can also find it magnitude and direction
Generally,
A = a•i + b•j
|A| = √(a²+b²)
<A = arctan(b/a)
So,
|A+B| = √(3²+4²) = √9+16 = √25
|A+B| = 5
And it's direction
< = arctan(y/x)
< = arctan(4/3)
< = 53.13°
Answer:
The energy ratio is 
Explanation:
The kinetic energy of the 20mph object is
,
and the kinetic of the same abject at 5mph is
therefore, the ratio of 
to 
is
Thus, the energy ratio is 
.
The rocket works on the principal of action and reaction. Newton's third law of motion.
