<span>We can use the ideal gas law PV=nRT
For the first phase
The starting temperature (T1) is 273.15K (0C). n is 1 mole, R is a constant, P = 1 atm, V1 is unknown.
The end temperature (T2) is unknown, n= 1 mol, R is a constant, P = 3*P1= 3 atm, V2=V1
Since n, R, and V will be constant between the two conditions: P1/T1=P2/T2
or T2= (P2*T1)/(P1) so T2= (3 atm*273.15K)/(1 atm)= 3*273.15= 816.45K
For the second phase:
Only the temperature and volume change while n, P, and R are constant between the start and finish.
So: V1/T1=V2/T2 While we don't know the initial volume, we know that V2=2*V1 and T1=816.45K
So T2=(V2*T1)/V1= (2*V1*T1)/V1=2*T1= 2*816.45K= 1638.9K
To find the total heat added to the gas you need to subtract the original amount of heat so
1638.9K-273.15K= 1365.75K</span>
Answer:
Atom
Explanation:
The smallest unit which maintains an element's properties is an atom.
Lattice energy of potassium nitrate (KNO3) = -163.8 kcal/mol
Hydration energy of KNO3 = -155.5 kcal/mole
Heat of solution is the amount of heat absorbed by water when 1 mole of KNO3 is dissolved in it
Heat of solution = Hydration energy - Lattice energy
= -155.5 -(-163.8) = 8.3 kcal/mol
1 kcal/mol = 4.184 kJ/mole
Therefore, 8.3 kcal/mole = 4.184 * 8.3 = 34.73 kJ/mol
Now, 34.73 kJ of heat is absorbed when 1 mole of KNO3 is dissolved
The given 105 kJ of heat would correspond to : 105/34.73 = 3.023 moles of KNO3
Molar mass of KNO3 = 101.1 g/mole
Mass of KNO3 = Molar mass * moles
= 101.1 * 3.023 = 305.63 g = 0.3056 kg
Plant cells have plastids, cell wall, large and permanent vacuoles whereas animal cells don't
