As an example, a 4.00-kg aluminum ball has an apparent mass of 2.10 kg when submerged in a particular liquid: calculate the dens
1 answer:
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Answer:
219.9208 m
Explanation:
The new length is given by
New length= Original length *(1-Temperature change*coefficient of
thermal expansion of steel)
Here, the change in temperature is
New length=
Therefore, the new length will be 219.9208 m
Answer:
b. 9.5°C
Explanation:
= Mass of ice = 50 g
= Initial temperature of water and Aluminum = 30°C
= Latent heat of fusion =
= Mass of water = 200 g
= Specific heat of water = 4186 J/kg⋅°C
= Mass of Aluminum = 80 g
= Specific heat of Aluminum = 900 J/kg⋅°C
The equation of the system's heat exchange is given by
The final equilibrium temperature is 9.50022°C