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ale4655 [162]
2 years ago
7

As an example, a 4.00-kg aluminum ball has an apparent mass of 2.10 kg when submerged in a particular liquid: calculate the dens

ity of the liquid.
Physics
1 answer:
azamat2 years ago
6 0

Answer:

1.2825 * 10^3 kg/m³

Explanation:

Given that :

Mass of aluminum ball (m1) = 4kg

Apparent mass of ball (m2) = 2.10 kg

Density of aluminum (d1) = 2.7 * 10^3 kg/m³

Density of liquid (d2) =?

Using the relation :

d1 / d2 = m1 / (m2 - m1)

(2.7 * 10^3) / d2 = 4 / (4 - 2.10)

2700 / d2 = 4 / 1.9

4 * d2 = 2700 * 1.9

4 * d2 = 5130

d2 = 5130 / 4

d2 = 1282.5 kg/m³

Hence, density of liquid = 1.2825 * 10^3

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Mrrafil [7]

Answer: Option (a) is the correct answer.

Explanation:

Global Positioning Systems (GPS) is a system which uses a network of satellites to construct maps. So, that it would be easy to trace location of a person, or to reach over a certain place.

It helps an individual by showing the route of destination wherever he/she wants to reach along with the total time to reach over the place.

Thus, GPS can determine the elevation of a given area and also it can determine latitude and longitude of a given area. As each GPS satellite broadcasts with a high power, narrow bandwidth, down link signal which can be received by our small hand held receiver antenna called mobile phone.

A GPS cannot determine the composition of soil on mountain ranges.

Thus, we can conclude that out of the given options, GPS can determine the composition of soil on mountain ranges is not true about the Global Positioning Systems (GPS).

7 0
3 years ago
A resistor with an unknown resistance is connected in parallel to a 13 Ω resistor. When both resistors are connected in parallel
larisa86 [58]

Answer:

R2 = 10.31Ω

Explanation:

For two resistors in parallel you have that the equivalent resistance is:

\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}\\\\      (1)

R1 =  13 Ω

R2 = ?

The equivalent resistance of the circuit can also be calculated by using the Ohm's law:

I=\frac{V}{R_{eq}}\\\\R_{eq}=\frac{V}{I}            (2)

V: emf source voltage = 23 V

I: current = 4 A

You calculate the Req by using the equation (2):

R_{eq}=\frac{23V}{4A}=5.75\Omega

Now, you can calculate the unknown resistor R2 by using the equation (1):

\frac{1}{R_2}=\frac{1}{R_{eq}}-\frac{1}{R_1}\\\\R_2=\frac{R_{eq}R_1}{R_1-R_{eq}}\\\\R_2=\frac{(5.75\Omega)(13\Omega)}{13\Omega-5.75\Omega}=10.31\Omega

hence, the resistance of the unknown resistor is 10.31Ω

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3 years ago
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