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Brrunno [24]
3 years ago
6

¿Qué ocurre como consecuencia de las corrientes de convección en la astenosfera?

Physics
1 answer:
Vladimir [108]3 years ago
6 0

Respuesta:En la astenosfera existen lentos movimientos de convección que explican la deriva continental. Además, el basalto de la astenosfera fluye por extrusión a lo largo de las dorsales oceánicas, lo cual hace que se renueve y expanda constantemente el fondo oceánico. :D

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Both acids and bases produce ions when dissolved in water. Propose a way to describe what
EleoNora [17]

Answer:

See explanation

Explanation:

Acids and bases contain ions that interact with water. According to the Arrhenius definition, acids are substances that produce hydrogen ion in water while bases are substances that produce hydroxide ion in water.

The pH scale is a graphic description of the hydrogen or hydroxide ion present in a sample. Since pH= -log[H^+], the higher the pH , the lower the hydrogen ion concentration and vice versa.

Similarly, pOH= -log [OH^-] , hence the more the OH^- concentration the lower the pOH.

However pH + pOH =14.

Thus the concentration of hydrogen or hydroxide ions present determines the pH of any solution.

6 0
3 years ago
Read 2 more answers
Karen runs sets in basketball practice. She starts from a line runs 2.0 m, returns to the line, runs 4.0 m, to the line, runs 6.
Aleonysh [2.5K]

D. distance = 23 m, displacement = + 1 m

Explanation:

Let's remind the difference between distance and displacement:

- distance is a scalar, and is the total length covered by an object, counting all the movements in any direction

- displacement is a vector connecting the starting point and the final point of a motion, so its magnitude is given by the length of this vector, and its direction is given by the direction of this vector.

In this case, the distance covered by Karen is given by the sum of all its movements:

distance = 2.0 m + 2.0 m+4.0 m+4.0 m +6.0 + 5.0 m=23.0 m

The displacement instead is given by the difference between the final point (1.0 m in front of the starting line) and the starting point (the starting line, 0 m):

displacement = +1.0 m-0 m=+1 m

8 0
3 years ago
The velocity of a particle traveling in a straight line is given by v = (6t - 3t²) m/s, where t is in seconds. If s = 0 when t =
qaws [65]

Answer

given,

v = (6 t - 3 t²) m/s

we know,

v = \dfrac{dx}{dt}

a = \dfrac{dv}{dt}

position of the particle

dx = v dt

integrating both side

\int dx = (6t - 3 t^2)\int dt

 x = 3 t² - t³

Position of the particle at t= 3 s

 x = 3  x 3² - 3³

 x = 0 m

now, particle’s deceleration

a = \dfrac{dv}{dt}

a = \dfrac{d}{dt}(6t - 3 t^2)

  a = 6 - 6 t

at t= 3 s

    a = 6 - 6 x 3

    a = -12 m/s²

distance traveled by the particle

  x = 3 t² - t³

at t = 0 x = 0

   t = 1 s   , x = 3 (1)² - 1³ = 2 m

   t = 2 s  ,  x = 3(2)² - 2³ = 4 m

   t = 3 s ,   x =  0 m

total distance traveled by the particle

D = distance in 0-1 s + distance in 1 -2 s + distance in 2 -3 s

D = 2 + 4 + 2 = 8 m

average speed of the particle

v_{avg} = \dfrac{distance}{time}

v_{avg} = \dfrac{8}{3}

v_{avg} =2.67\ m/s

8 0
3 years ago
What is the speed of a walking person in m/s if the person travels 1000 m in 20 minutes?
Nata [24]

Answer:

0.83m/s

Explanation:

Given parameters:

distance  = 1000m

time taken  = 20min

Unknown:

Speed of the walking person  = ?

Solution:

To solve this problem;

    Speed  = \frac{distance}{time taken}

  Time taken should be in seconds;

                 1 min   =  60s

                 20min  = 20 x 60  = 1200s

Speed  = \frac{1000}{1200}   = 0.83m/s

8 0
3 years ago
El tubo de entrada que suministra presión de aire para operar un gato hidráulico tiene 2 cm de diámetro. El pistón de salida es
topjm [15]

Answer:

P₁ = 219.3 Pa

Explanation:

This fluid mechanics problem, we can use that the pressure is distributed with the same value throughout the system, which is Pascal's principle.

Let's use the subinidce1 for the small diameter and the subscript 2 for the larger diameter.

              P₁ = P₂

pressure is defined by

             P = F / A

we subtitute

             F₁ / A₁ = F₂ / A₂

             F₁ = F₂ A₁ / A₂

the area in a circle is

             A = π r² = π d² / 4

we substitute

            F₁ = F₂ (d₁ / d₂)²

we calculate

           F₁ = 17640 (2/32)²

           F₁ = 68.9 N

Having the force to be applied we can find the air pressure on the small plunger

          P₁ = F₁ / A₁

          P₁ = F₁ 4 / π d₁²

let's calculate

          P₁ = 68.9 4 / (π 0.02²)

          P₁ = 219.3 Pa

3 0
3 years ago
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