Answer:
As the velocity of light is constant so the acceleration of the light is equal to zero.
a= dv/dt
Explanation:
Answer:
39.7 m
Explanation:
First, we conside only the last second of fall of the body. We can apply the following suvat equation:

where, taking downward as positive direction:
s = 23 m is the displacement of the body
t = 1 s is the time interval considered
is the acceleration
u is the velocity of the body at the beginning of that second
Solving for u, we find:

Now we can call this velocity that we found v,
v = 18 m/s
And we can now consider the first part of the fall, where we can apply the following suvat equation:

where
v = 18 m/s
u = 0 (the body falls from rest)
s' is the displacement of the body before the last second
Solving for s',

Therefore, the total heigth of the building is the sum of s and s':
h = s + s' = 23 m + 16.7 m = 39.7 m
Answer:
6.21 m/s
Explanation:
Using work energy equation then

where d is displacement from initial to final position, v is velocity and subscripts a and b are position A and B respectively, m is mass of collar, g is acceleration due to gravity
Substituting 1 Kg for m, 0.4m for h,
as 0, 9.81 for g then

Winds are deflected to the right as they move into a low pressure area in the Northern Hemisphere.
<u>Explanation:</u>
Winds decide the motion of ocean currents which forms the surface waves in the Earth's atmosphere to maintain the pressure region. The motion of ocean currents is based on Coriolis force which states the direction of motion of an object in a rotating system.
In the case of Earth, the Coriolis force has an effect on the ocean currents which are deflected from maximum to minimum pressure region in a curved path. So the winds formed by the ocean currents will generally get deflected at the right as they move into a low pressure area at the Northern Hemisphere from the high pressure region.