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butalik [34]
2 years ago
7

To appreciate the strength of gravity, calculate the number of steel cables that would be required, in the absence of gravity, t

o hold the Moon in orbit about the Earth. Each cable has a cross-sectional area of 1 square meter, and the tensile strength of steel is 370 MPa.
Physics
1 answer:
Serga [27]2 years ago
4 0

Answer:

N=5.36*10^{17}

Explanation:

From the question we are told that:

Tensile strength of steel \sigma_c=370 MPa.=370*10^6

Cross-sectional area A= 1m^2

Generally the equation for Total Force is mathematically given by

 F = \frac{G M m}{r^2}

 F=\frac{6.67*10^{-11}*7.35*10^{22}*5.97*10^{24}}{(384*10^3)^2}

Since this is the force of each cable

 F=\sigma_c NA

 F= 370*10^6*N*1

Therefore

 370*10^6*N*1=\frac{6.67*10^{-11}*7.35*10^{22}*5.97*10^{24}}{(384*10^3)^2}

 N=5.36*10^{17}

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Answer:

12 A

Explanation:

V= I * R

V/R = I

120 V /10 Ω  = 12 AMPS

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1 year ago
Mr. Adams asked his students to write the chemical symbol for the element zinc. He wrote the students’ answers on the whiteboar
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The chemical symbol for the element zinc is Zn.

<h3>What is element?</h3>

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Thus, the student wrote Zn as the chemical symbol of Zinc on the whiteboard.

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4 0
2 years ago
A 0.80-μm-diameter oil droplet is observed between two parallel electrodes spaced 11 mm apart. The droplet hangs motionless if t
Arisa [49]

A) 2.4\cdot 10^{-16}kg

The radius of the oil droplet is half of its diameter:

r=\frac{d}{2}=\frac{0.80 \mu m}{2}=0.40 \mu m = 0.4\cdot 10^{-6}m

Assuming the droplet is spherical, its volume is given by

V=\frac{4}{3}\pi r^3 = \frac{4}{3}\pi (0.4\cdot 10^{-6} m)^3=2.68\cdot 10^{-19} m^3

The density of the droplet is

\rho=885 kg/m^3

Therefore, the mass of the droplet is equal to the product between volume and density:

m=\rho V=(885 kg/m^3)(2.68\cdot 10^{-19} m^3)=2.4\cdot 10^{-16}kg

B) 1.5\cdot 10^{-18}C

The potential difference across the electrodes is

V=17.8 V

and the distance between the plates is

d=11 mm=0.011 m

So the electric field between the electrodes is

E=\frac{V}{d}=\frac{17.8 V}{0.011 m}=1618.2 V/m

The droplet hangs motionless between the electrodes if the electric force on it is equal to the weight of the droplet:

qE=mg

So, from this equation, we can find the charge of the droplet:

q=\frac{mg}{E}=\frac{(2.4\cdot 10^{-16}kg)(9.81 m/s^2)}{1618.2 V/m}=1.5\cdot 10^{-18}C

C) Surplus of 9 electrons

The droplet is hanging near the upper electrode, which is positive: since unlike charges attract each other, the droplet must be negatively charged. So the real charge on the droplet is

q=-1.5\cdot 10^{-18}C

we can think this charge has made of N excess electrons, so the net charge is given by

q=Ne

where

e=-1.6\cdot 10^{-19}C is the charge of each electron

Re-arranging the equation for N, we find:

N=\frac{q}{e}=\frac{-1.5\cdot 10^{-18}C}{-1.6\cdot 10^{-19}C}=9.4 \sim 9

so, a surplus of 9 electrons.

3 0
3 years ago
A molecular compound is formed when a chemical reaction occurs between atoms of
scoundrel [369]

Answer:

the reaction mechanism occurs by electrostatic attraction of some type, where electrons are shared or transferred into the atoms and the new molecular compound is established more betabel than the indigenous atoms

Explanation:

Molecules are formed by atoms, through those of many chemical reactions that are processes by which the energy of the products is less than the energy of the reactants.

In these processes, in general, the reaction mechanism occurs by electrostatic attraction of some type, where electrons are shared or transferred into the atoms and the new molecular compound is established more betabel than the indigenous atoms

6 0
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The free-body diagram below represents the force of several vehicles driving across a bridge. Assume that the bridge is in stati
krek1111 [17]

In order to calculate the unknown reaction force, we need to know that the sum of forces pointing down is equal the sum of the forces pointing up, so all forces will be in equilibrium.

So we have:

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7 0
1 year ago
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