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Marianna [84]
2 years ago
5

Kiley went 5.7 km/h north and then went 5.8 km/h west. From start to finish, she went 8.1 km/h northwest.

Physics
2 answers:
cluponka [151]2 years ago
8 0

Explanation :

Instantaneous velocity: It is defined as the velocity at a particular instant of time.

Average velocity is the ratio of total displacement covered by an object divided by the total time taken.

It is given that, Kiley went 5.7 km/h north and then went 5.8 km/h west. Here, both direction as well as magnitude of velocity is given. This implies the instantaneous speeds.

The resultant of these two velocities would be :

v=\sqrt{ (v_N)^2+(-v_w)^2

v=\sqrt{(5.8\ km/h)^2+(5.7\ km/h)^2}

v=8.1\ km/h

She went 8.1 km/h northwards. This implies resultant velocity i.e. average speed.

So, the correct option is (a).

Hence, this is the required solution.

TiliK225 [7]2 years ago
6 0
<span>5.7 km/h north and 5.8 km/h west are instantaneous velocities, while 8.1 km/h is the average velocity.

This is because each value has a magnitude and direction so it is a velocity. Moreover, the 8.1 km/h is the resultant of the two velocities so it is the average while the other two are instantaneous.</span>
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vekshin1

Answer:

= 7.07 m

Explanation:

The Tarzan reaches bottom of swing after descending 2.5 m,

change in his potential energy equals his kinetic energy at bottom of swing

m g h = (1/2) m v²   ,  

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v = ( 2 g h )1/2

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A car and a motorcycle start from rest at the same time on a straight track, but the motorcycle is 25.0 m behind the car. The ca
sergeinik [125]

Answer:

t = 8.45 sec

car distance d = 132.09  m

bike distance d = 157.08 m

Explanation:

GIVEN :

motorcycle is 25 m behind the car , therefore distance need to covered by bike to overtake car is 25+ d, when car reache distance d at time t

for car

by equation of motion

d  = ut + \frac{1}{2}at^2

u = 0 starting from rest

d = \frac{1}{2}at^2

t^2 = \frac{2d}{a}

for bike

d+25 = 0 + \frac{1}{2}*4.40t^2

t^2= \frac{d+25}{2.20}

equating time of both

\frac{2d}{a} = \frac{d+25}{2.20}

solving for d we get

d = 132 m

therefore t is= \sqrt{\frac{2d}{a}}

t =  \sqrt{\frac{2*132}{3.70}}

t = 8.45 sec

each travelled in time 8.45 sec as

for car

d = \frac{1}{2}*3.70 *8.45^2

d = 132.09  m

fro bike

d = \frac{1}{2}*4.40 *8.45^2

d = 157.08 m

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</span>
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