Variables are often used in equations to represent what? coefficients, data, physical constants or exponents

Advantages of using tidal power include _____. no air pollution tides are predictable low environmental impact all of these

lana66690 [7]

Advantages of using tidal power include no air pollution, no air pollution and low environmental impact.

<h3>What is Tidal Power?</h3>

The rush of ocean waters during tide changes is what generates tidal energy. A renewable energy source is tidal energy.

In places with a wide tidal range—the distance between high tide and low tide—engineers devised methods to harness tidal movement to generate power during the 20th century. Each technique turns tidal energy into electricity using specialised generators.

Production of tidal energy is still in its infancy. So yet, hardly much electricity has been generated. There aren't many commercial-scale tidal power facilities in operation worldwide. The first was at France's La Rance. The Sihwa Lake Tidal Power Station in South Korea is the biggest facility. There are very few places in the United States where tidal energy might be generated at a competitive price and no tidal plants. Russia, Canada, France, England, and China have the most potential for using this kind of energy.

Advantages of using tidal power include no air pollution, no air pollution and low environmental impact.

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3 0

1 year ago

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Two small metallic spheres with equal mass are suspended as pendulums by strings of length L. The sphereshave the same electric

love history [14]

Answer:

Two small metallic spheres with equal mass are suspended as pendulums by strings of length L. The sphereshave the same electric charge and come to equilibrium with each string at an angle of Θ = 10.00° with the vertical. What happens if the electric charges are decreased?(D)

Explanation:

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3 0

3 years ago

You're driving your new sports car at 85 mph over the top of a hill that has a radius of curvature of 525 m.

Bumek [7]

Explanation:

It is given that,

Speed of the sports car, v = 85 mph = 37.99 m/s

The radius of curvature, r = 525 m

Let $W_N$ is the normal weight and $W_A$ is the apparent weight of the person. Its apparent weight is given by :

$W_A=mg-\dfrac{mv^2}{r}$

So, $\dfrac{W_A}{W_N}=\dfrac{mg-\dfrac{mv^2}{r}}{mg}$

$\dfrac{W_A}{W_N}=\dfrac{g-\dfrac{v^2}{r}}{g}$

$\dfrac{W_A}{W_N}=\dfrac{9.8-\dfrac{(37.99)^2}{525}}{9.8}$

$\dfrac{W_A}{W_N}=0.719$

or

$\dfrac{W_A}{W_N}=71.9\%$

Hence, this is the required solution.

5 0

3 years ago

What distance does light travel in water, glass, and diamond during the time that it travels 1.0 m in vacuum? The refractive ind

lidiya [134]

Answer:

refractive index for water,glass,diamond are 0.752m, 0.667m, 0.413m respectively

Explanation:

refractive index (n) = $\frac{velocity of light in air/vacuum}{velocity of light in substance}$

velocity = $\frac{distance}{time}$

The time for travel is kept constant for all mediums.

refractive index (n) = $\frac{\frac{distance in vacuum}{time} }{\frac{distance in medium}{time} }\\ \\=\frac{distance in vacuum}{distance in medium}$

distance in medium = $\frac{distance in vacuum}{refractive index of medium}$

$S_{medium} = \frac{S_{vacuum} }{n_{medium} }$

For water, n= 1.33

$S_{water} = \frac{1 }{1.33}$

$S_{water} = 0.752m$

For glass, n=1.5

$S_{glass}= \frac{1 }{1.5}$

$S_{glass} = 0.667m$

For diamond, n= 2.42

$S_{diamond} = \frac{1 }{2.42}$

$S_{diamond} = 0.413m$

3 0

3 years ago

The beginning development of a star is marked by a supernova explosion, with the gases present in the nebula being forced

GenaCL600 [577]

The beginning development of a star is marked by a supernova explosion, with the gases present in the nebula being forced to scatter. As the star shrinks, radiation of the surface increases and create pressure on the outside shell to push it away and forming a planetary nebula or white dwarf.

4 0

3 years ago