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Elina [12.6K]
3 years ago
10

Food is digested to the molecularlevel, absorbed, and then carried to the cells. The dissolved waste molecules produced by the c

ells are removed primarily from the blood by the
Chemistry
1 answer:
s2008m [1.1K]3 years ago
8 0

Answer:

biohemisphere

Explanation:

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Name the difference(s) between an plant and animal cell? Question 1 options: a animal cells do not contain chloroplasts b animal
Bogdan [553]

answer should be d :)

7 0
3 years ago
When electricity flows through water, the water molecules split into molecules of hydrogen and oxygen gas. How many oxygen (O2)
ikadub [295]
That would be one oxygen molecule.
5 0
3 years ago
Read 2 more answers
H3PO4 + Ca(OH)2 → Ca(H2PO4)2 + H2O
aniked [119]

Given question is incomplete. The complete question is as follows.

Balance the following equation:

H_3PO_4 + Ca(OH)_2 \rightarrow Ca(H_2PO_4)_2 + H_2O

Answer: The balanced chemical equation is as follows.

2H_3PO_4 + Ca(OH)_2 \rightarrow Ca(H_2PO_4)_2 + 2H_2O

Explanation:

When a chemical equation contains same number of atoms on both reactant and product side then this equation is known as balanced equation.

For example, H_3PO_4 + Ca(OH)_2 \rightarrow Ca(H_2PO_4)_2 + H_2O

Number of atoms on reactant side:

H = 5

P = 1

O = 6

Ca = 1

Number of atoms on product side:

H = 6

P = 2

O = 9

Ca = 1

In order to balance this equation, we will multiply H_3PO_4 by 2 on reactant side and we will multiply H_2O by 2 on product side. Hence, the balanced chemical equation is as follows.

2H_3PO_4 + Ca(OH)_2 \rightarrow Ca(H_2PO_4)_2 + 2H_2O

8 0
3 years ago
Calculate the molarity of a solution that contains 4.7 moles in 5.2 liters.
AleksAgata [21]

Answer:

0.9M

Explanation:

molarity = mols/L

M=4.7mol/5.2L

= 0.9M

4 0
3 years ago
Calculate the solubility of mn(oh)2 in grams per liter when buffered at ph=7.0. assume that buffer capacity is not exhausted
Vanyuwa [196]
When PH + POH = 14 
∴ POH = 14 -7 = 7

when POH = -㏒[OH-]

          7    = -㏒ [OH-]
∴[OH-] = 10^-7

by using ICE table:

           Mn(OH)2(s) ⇄  Mn2+ (aq)  + 2OH-(aq)
initial                              0                     10^-7
change                           +X                      +2X
Equ                                 X                  (10^-7 + 2X)

when Ksp = [Mn2+][OH-]^2

when Ksp of Mn(OH)2 = 4.6 x 10^-14

by substitution:

4.6 x 10^-14 = X*(10^-7+2X)^2  by solving this equation for X

∴ X =2.3 x 10-5 M

∴ The solubility of Mn(OH)2 in grams per liter (when the molar mass of Mn(OH)2 = 88.953 g/mol
= 2.3 x10^-5 moles/L * 88.953 g/mol

= 0.002 g/ L
3 0
3 years ago
Read 2 more answers
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