As 
, the 
term will converge to 0, so the limit is 2 (B).
First find the volume of the cylinder, then the volume of the cone, and after you can add the two volumes.
Cylinder:
V = π r^2 h
h = 12 inches
r = 4 inches
V = π(4^2)(12)
V = 192π
Cone:
V = 1/3 π r^2 h
h = 6 inches
r = 4 inches
V = 1/3 π (4^2)(6)
V = 32π
Now adding the two volumes, 192π + 32π = 224π cubic inches
<span>1) 3x + y = 23
6x + y = 44
Subtract 1st from 2nd,
3x = 21
x = 7
Then, y = 23 - 3(7) = 2
In short, Your Answer would be: (7, 2)
2) </span><span>4x - 3y = 21
2x + 3y = 33
Add the equations,
6x = 54
x = 9
Then, 2(9) + 3y = 33
3y = 33 - 18
y = 15/3
y = 5
In short, Your Answer would be: (9, 5)
3) </span><span>5x + 2y = 13
6y + 5x = 29
Subtract 1st from 2nd equation,
4y = 16
y = 4
Then, 5x = 13 - 2(4)
x = 5/5 = 1
In short, Your Answer would be: (1, 4)
4) </span><span>5x - 4y = 2
10x - 4y = 32
Subtract 1st from 2nd equation,
5x = 30
x = 6
Then, 5(6) - 2 = 4y
y = 28/4 = 7
In short, Your Answer would be: (6, 7)
5) </span><span>2x + 7y = 48
x + 3y = 21
Here, x = 21-3y
Substitute in in 1st equation,
2(21-3y) + 7y = 48
42 - 6y + 7y = 48
y = 6
Then, x = 21 - 3(6) = 3
In short, Your Answer would be: (3, 6)
6) </span><span>8x - 3y = 44
2y - 4x = -20
Multiply 2nd equation by 2
-8x + 4y = -40
Now, add it to 1st equation,
y = 4
Then, 2(4) - 4x = -20
4x = 8 + 20
x = 28/4 = 7
In short, Your Answer would be: (7, 4)
Hope this helps!</span>
Answer:
Step-by-step explanation:
