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Gnesinka [82]
2 years ago
10

A certain Diesel engine performs 372 of work in each cycel wth an efficieny of 33.0 percent.How much energy is transferred from

the engine to the exhaust and cooling system as heat
Physics
1 answer:
lesantik [10]2 years ago
8 0

Answer:

122.76J

Explanation:

Given data

work done= 372 Joules

efficiency= 33%

Required

We want to compute the value of the work that is 33%

= 33/100* 372

= 0.33*372

= 122.76J

Hence 122.76J of work is transferred from the engine to the exhaust

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1. A force acting on an object in the upward direction is 3 N. The force that would
DENIUS [597]

Answer:

See the explanation below

Explanation:

We must perform a sum of forces on the body, that sum of forces is equal to zero. That is, the body is in balance and does not move.

ΣF = 0

3 - 3 = 0

This force is negative and acts by pointing downwards.

4 0
3 years ago
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numerical question : what is the required heat to raise the temperature of 2 kg parrafin by 10 Celsius if 44000 joules is requir
kirill115 [55]

Answer:

The heat energy required is, E = 2200 J

Explanation:

Given,

The mass of paraffin, m = 2 Kg

The energy required to raise the temperature of the paraffin by 200° C = 44000 J

Then the heat energy required to raise the temperature of the paraffin by 10° C is given by,

Since 44000 J raises temperature by 200° C, then

                              E = 44000 J / 20

                                 = 2200 J

Hence, the energy required to raise the temperature of the paraffin by 10° C is, E = 2200 J

8 0
2 years ago
An electron in a vacuum is first accelerated by a voltage of 51400 V and then enters a region in which there is a uniform magnet
zimovet [89]

Answer:

       F = 8.6 10⁻¹² N

Explanation:

For this exercise we use the law of conservation of energy

Initial. Field energy with the electron at rest

         Em₀ = U = q ΔV

Final. Electron with velocity, just out of the electric field

         Emf = K = ½ m v²

          Em₀ = Emf

          e ΔV = ½ m v²

          v =√ 2 e ΔV / m

          v = √(2 1.6 10⁻¹⁹ 51400 / 9.1 10⁻³¹)

           v = √(1.8075 10¹⁶)

           v = 1,344 10⁸ m / s

Now we can use the equation of the magnetic force

         F = q v x B

Since the speed and the magnetic field are perpendicular the force that

        F = e v B

        F = 1.6 10⁻¹⁹  1.344 10⁸ 0.4

       For this exercise we use the law of conservation of energy

Initial. Field energy with the electron at rest

         Emo = U = q DV

Final. Electron with velocity, just out of the electric field

         Emf = K = ½ m v2

          Emo = Emf

          .e DV = ½ m v2

          .v = RA 2 e DV / m

          .v = RA (2 1.6 10-19 51400 / 9.1 10-31)

           .v = RA (1.8075 10 16)

           .v = 1,344 108 m / s

Now we can use the equation of the magnetic force

         F = q v x B

Since the speed and the magnetic field are perpendicular the force that

        F = e v B

       F = 1.6 10-19 1,344 108 0.4

       F = 8.6 10-12 N

5 0
2 years ago
Why might some rivers form canyons and other form valleys??
kap26 [50]

Valleys are one of the most common landforms on the Earth and they are formed through erosion or the gradual wearing down of the land by wind and water. In river valleys ​for example, the river acts as an erosional agent by grinding down the rock or soil and creating a valley

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3 years ago
WILL MARK BRAINLIST
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Answer:

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transitive verb

1: to enclose or enfold completely with or as if with a covering

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