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3 years ago

What is the relationship between the weight of objects and the sum of their parts?

Physics

1 answer:

alexandr1967 [171]3 years ago

4 0

Answer:

No matter how parts of an object are assembled, the weight of the whole object is always the same as the sum of the parts; and when a thing is broken into parts, the parts have the same total weight as the original thing.

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A force which resist the relative motion of two bodies in direct contact is called _______

Elena-2011 [213]

Frictional Force is the answer..

Hope it helps

3 0

3 years ago

A 7.0 kg bowling ball has a moment of inertia of 2.8x10-2 kg m2, and a radius of 0.10 m. If it rolls down the lane at an angular

slega [8]

Hi there!

Angular momentum is equivalent to:

$\large\boxed{L = I\omega}$

L = angular momentum (kgm²/s)

I = moment of inertia (kgm²)

ω = angular velocity (rad/sec)

Plug in the given values for moment of inertia and angular speed:

$L = (0.028)(40) = \boxed{1.12 kgm^2/s}$

8 0

2 years ago

If we double the frequency of a system undergoing simple harmonic motion, which of the following statements about that system ar

AnnyKZ [126]

Answer:

a. The angular frequency is doubled.

e. The period is reduced to one-half of what it was.

Explanation:

Angular frequency is given as;

ω = 2πf

$\frac{\omega _1}{f_1} = \frac{\omega _2}{f_2}$

when the frequency is doubled

$\frac{\omega _1}{f_1} = \frac{\omega _2}{(2f_1)} \\\\\omega _1 = \frac{\omega _2}{2}\\\\\omega _2 = 2\omega _1$

Thus, the angular frequency will be doubled.

Amplitude in simple harmonic motion is the maximum displacement.

Frequency is related to period in simple harmonic motion as given in the equation below;

$f = \frac{1}{T} \\\\f_1T_1= f_2T_2\\\\T_2 = \frac{f_1T_1}{f_2}$

when the frequency is doubled;

$T_2 = \frac{f_1T_1}{2f_1} \\\\T_2 = \frac{T_1}{2}$

Thus, the period will be reduced to one-half of what it was.

5 0

3 years ago

2. Can you place three forces of 5g, 6g, and 12g so they are in equilibrium. Justify your answer.

Bond [772]

Answer:

We cannot place three forces of 5g, 6g, and 12g in equilibrium.

Explanation:

Equilibrium means their sum must be zero.

Here the forces are 5g, 6g, and 12g.

For number of forces to be in equilibrium the magnitude of largest vector should be less than sum of the magnitude of other vectors.

Here

Magnitude of largest force = 12 g

Sum of magnitudes of other forces = 5g + 6g = 11g

Magnitude of largest force > Sum of magnitudes of other forces

So this forces cannot form equilibrium.

We cannot place three forces of 5g, 6g, and 12g in equilibrium.

4 0

3 years ago

Urination is one of the key mechanisms for losing fluid from the human body.

serious [3.7K]

This is a true statement

7 0

3 years ago

Read 2 more answers