Answer:
In the 1H NMR spectrum of ethanol three different signals are observed, this is due to the existence of 3 types of hydrogens with different chemical environment. Hydrogens A (3.57 ppm) are more screened than C (1.10 ppm) due to the presence of oxygen (electonegative atom that removes electron density). The chemical environment of hydrogen B (4.78 ppm), attached directly to oxygen, is also different by resonating at a frequency different from the previous ones.
The hydroxylic hydrogen produces a singlet, the pair of carbon hydrogens one give rise to a quadruplet and the three hydrogens of carbon two produce a triplet.
Explanation:
Answer:
2 atoms of H in the products side
Explanation:
3NO₂ + H₂O → NO + 2HNO₃
In product side: 3 N (1 from NO and 6 from nitric acid), 7 O (6 from nitric acid + 1 from NO), 2 H
In reactant side: 3 N, 7 O (6 from the dioxide + 1 from water) and 2 H
Answer:
i)
1 is Argon
2 is Kalium
3 is Calcium
ii)
Y belongs to alkaline metals
Z belongs to alkaline earth metals
iii)
Kalium (Y) is alkaline metal
N=V/Vm
n - the number of moles
V - the volume
Vm=22.4 L/mol - the standard molar volume of gas
Bond Order = [Σ (bonding e-) - Σ (antibonding e-)]/2
<span>Be2 = 4e = σ1(2e) σ2*(2e) σ3(0) π1(0) π2*(0) σ4*(0) bo = 0 </span>
<span>[Be2]+ = 3e = σ1(2e) σ2*(1e) σ3(0) π1(0) π2*(0) σ4*(0) bo = 0.5 </span>
<span>[Be2]+ would be more likely to exist since it has a bond order of 0.5 whereas Be2 has zero bond order</span>
