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2 years ago

How many valence electrons are represented in the following electron configuration? 1s22s22p5

1 answer:

Alex2 years ago

7 0

Answer is: d) 7.
Electron configuration: 1s²2s²2p⁵.
Valence electrons are in 2s and 2p orbitals.
Valence electrons are outer shell electrons (transition metal can have a valence electrons in an inner shell) that is associated with an atom and they can form chemical bond. Valence eletrons determine chemical proporties of element.

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In what type of environment would you most likely find Fish Species 1? Explain your answer.

KengaRu [80]

Answer:

Fish are more likely to hold a soft bait longer. ... Signs of small fish activity can lead you to fishing hot spots. ... Cover can be loosely defined as anything that will hide or protect the fish.

Explanation:

Fishes live in virtually all aquatic habitats. Different species of fish are adapted for different habitats: rocky shores, coral reefs, kelp forests, rivers and streams, lakes and ponds, under sea ice, the deep sea, and other environments of fresh, salt, and brackish water.

5 0

3 years ago

Read 2 more answers

All of the following statements about solutions are correct Except?

Tasya [4]

Answer:

A solution is a heterogeneous mixture

Explanation:

This statement that a solution is a heterogeneous mixture is completely and totally wrong.

A solution is a homogeneous mixture.

Homogeneous mixtures have their constituents existing in just one phase.

It is a homogeneous mixture of solutes and solvents.
In a solution, the solutes particles are distributed uniformly in the solvent.
The solute is the substance that is dissolved to make the solution.
Solutes are usually present in a small amount than the solvent.
The solvent acts as the dispersing medium which allows the solute to go into the solution.
The solute can be solid, liquid or gas.

4 0

3 years ago

What are the products in this chemical reaction? 2H3PO4+3Ca(OH)2→Ca3(PO4)2+6H2O

finlep [7]

<h2>Answer:C</h2>

Explanation:

A chemical equation is a equation that describes a corresponding chemical reaction.

A chemical reaction is generally written as

$reactants$ → $products$

$reactants$ refer to all the reactants involved in the chemical reaction.

Reactants are usually written on the left hand side of the chemical equation.

$products$ refer to all the products formed in the chemical reaction.

products are usually written on the right hand side of the chemical equation.

In the given reaction, $Ca_{3}(PO_{4})_{2}$ , $H_{2}O$ are written on the right side of the equation.

So, $Ca_{3}(PO_{4})_{2}$ , $H_{2}O$ are the products.

5 0

3 years ago

Read 2 more answers

Hello this is my 3 attempt, please someone answer this i'm begging you.

denis23 [38]

Answer:

Explanation:

No worries, I got you :)

So for the first question, you need to use PV=nRT to find the n, or in other words, the number of moles. Then, you can find the molar mass since you know the grams and the moles

110 kPa / 101.3 = 1.085 atm (I converted it to atm so I can use the .08206 L atm/ k mol for the rate)

550 ml / 1000 = .550 L (I converted mL to L in order to use the .08206 L atm/ k mol for the Rate)

28.5 c + 273 = 301.5 K (I converted C to K in order to use the .08206 L atm/ k mol for the Rate)

PV=nRT

(1.085) (.550 L) = n (0.08206) (301.5)

Divide the (0.08206) (301.5) to get n alone:

(1.085) (.550 L) / (0.08206) (301.5) = n

When I divided, I got n= .02412 moles, and since we have 1.88g , we divide the 1.88 by .02412 to get the molar mass (grams/mole)

77.94 g/mole is the molar mass

we know that there are 3 H's in the compound, so we do 3(1.008) and subtract 77.94 by what you get.

3 x 1.008 = 3.024 -----> 77.94-3.024 = 74.9

Now we look at the periodic table and try to find an element that has a molar mass of 74.9

Arsenic (As) has a molar mass of 74.922, which is close enough. Plus, Arsenic has a charge of 3, so it fits with the 3 hydrogens.

5 0

2 years ago

Cyclopropane is more reactive than most cycloalkanes. What factors lead to cyclopropane being less stable than the other cycloal

maw [93]

Answer: The factor that lead to cyclopropane being less stable than the other cycloalkanes is the presence of a RING STRAIN.

Explanation:

In organic chemistry, the end carbon atoms of an open aliphatic chain can join together to form a closed system or ring to form cycloalkanes. Such compounds are known as cyclic compounds. Examples include cyclopropane, cyclobutane, cyclopentane and many among others.

Cyclopropane is less stable than other cycloalkanes mentioned above because of the presence of ring strain in its structural arrangement. The ring strain is the spatial orientation of atoms of the cycloalkane compounds which tend to give off a very high and non favourable energy. The release of heat energy which is stored in the bonds and molecules cause the ring to be UNSTABLE and REACTIVE.

The presence of the ring strain affects mainly the structures and the conformational function of the smaller cycloalkanes. cyclopropane, which is the smallest cycloalkane than the rest mentioned above, contains only 3 carbons with a small ring.

8 0

2 years ago