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3 years ago

How can I change my Brainly username?

2 answers:

8 0

In the current brainly version, unfortunately you could not change your username.

The only way is to create a new account, but of course all of your points will be gone

mina [271]3 years ago

4 0

Answer:

Hi there! For changing your username you can contact to administrator of the site. If you are using app then go to message option. Then search "rishilaugh" then you can message him.

Explanation:

You might be interested in

Two stars M1 and M2 of equal mass make up a binary star system. They move in a circular orbit that has its center at the midpoin

ozzi

Answer:

V = 365643.04 m/s

Explanation:

mass of the sun = 1.99 x 10^{30} kg

mass of M1 = mass of M2 = 6.95 solar mass = 6.95 x 1.99 x 10^{30} = 13.8305x 10^{30} kg

orbital period of each star (T) = 2.20 days = 2.20 x 24 x 60 x 60 =190,080 s

gravitational constant (G) = 6.67 x 10^{-11} N m2/kg2

orbital speed (V) = $\sqrt{\frac{G(M1+M2)}{r} }$

we need to find the orbital radius (r) before we can apply the formula above and we can get it from Kepler's third law, $T^{2} = r^{3}$ x k

where

T = orbital period

r = orbital radius

k = $\frac{4n^{2} }{G(M1+M2)}$ (take note that π is shown as $n$ )

making r the subject of the formula we now have

$r = (\frac{G(M1+M2).T^{2}}{4n^{2} } )^{\frac{1}{3} }$ (take note that π is shown as $n$ )

$r = (\frac{ 6.67 x 10^{-11} ( 13.8305x 10^{30}+ 13.8305x 10^{30} )x190080^{2}}{4x3.142^{2} } )^{\frac{1}{3} }$

r = 1.38 x 10^{10} m

Now that we have the orbital radius (r) we can substitute all required values into the formula for orbital speed

orbital speed (V) = $\sqrt{\frac{G(M1+M2)}{r} }$

$V = \sqrt{\frac{6.67 x 10^{-11} ( 13.8305x 10^{30}+ 13.8305x 10^{30}}{1.38 x 10^{10} } }\\$

V = 365643.04 m/s

3 0

3 years ago

How would the amount of potential energy stored in the bungee cord compare to

Musya8 [376]

If the spring constant of the bungee rope is greater than that of a rubber band, it will have more elastic potential energy. However, if the spring constant of the rubber band is greater than that of the bungee rope, the rubber band will have more elastic potential energy.

<h3>Elastic Potential energy </h3>

Elastic Potential energy is the stored in a elastic string which has been compressed or stretched.

The formula for calculating elastic potential energy is given as:

Elastic Potential = 1/2 Kx^2

where

K is the spring constant of elastic material
x is the distance if compression or stretch

The elastic potential of an elastic material depends on the spring constant and the distance stretched or compressed.

Since the bungee rope and the rubber band are stretched the same distance, their elastic potential energy depends on their spring constant.

Therefore, if spring constant of the bungee rope is greater than that of a rubber band, it will have more elastic potential energy. However, if the spring constant of the rubber band is greater than that of the bungee rope, the rubber band will have more elastic potential energy.

Learn more about elastic potential energy at: brainly.com/question/1075827

3 0

2 years ago

What is the mass of a substance with a density of 9g/cm3 and a volume of 4cm3

Kazeer [188]

Answer:

p= 3 g/cm³

density formula: p= m/V; p= p, m= 9 g, V= 3

p= (9)/(3)

p= 3

p= 3 g/cm³

Explanation:

plz mark bainliest

5 0

2 years ago

A basket has a mass of 5.5 kg. Find the magnitude of the normal force if the basket is at rest on a ramp inclined above the hori

storchak [24]

Here is the correct answer of the given problem above.
Given that the basket has a mass of 5.5kg, the magnitude of the normal force if the basket is at rest on a ramp inclined above the horizontal is at 12 degrees. The solution is simple:
<span>Fn at rest = lmgl </span>
<span>= 5.5kg (9.80N/kg)
=</span><span> mgCos12degrees
Hope this answer helps. </span>

8 0

3 years ago

Read 2 more answers

^^ help :c

ipn [44]

I need help to I have a test and I need help to

6 0

3 years ago