According to Newton's Second Law, the force of the club hitting the golf ball will cause it to accelerate. At the moment of impa
ct, according to Newton's Third Law, A) the club hits the ball with twice as much force as the golf ball pushes back
B) the club pushes against to golf ball with a force equal and opposite to the force of the golf ball on the club
C) the ball puts more force on the club than the club on the ball
D) the force of the club on the ball is a balanced force, making the golf ball accelerate
<h3>According to Newton's third law, for every reaction there will be equal and opposite reaction</h3>
Here in this case the force of the club hitting the golf ball will be in one direction and the force acting on club due to golf ball will be in opposite direction and magnitude of this force will be same as the magnitude of the force of the club hitting the golf ball
In this case the action will be the force of the club hitting the golf ball and reaction will be the force acting on club due to golf ball
∴ The club pushes against to golf ball with a force equal and opposite to the force of the golf ball on the club
the club pushes against to golf ball with a force equal and opposite to the force of the golf ball on the club
Explanation:
At the moment of impact of the club and the golf ball according to Newton's Third Law, the club pushes against to golf ball with a force equal and opposite to the force of the golf ball on the club.
According to newton's third law of motion, actions and reaction are equal and opposite e.g recoil of a gun. The force (bullet) acts in the forward direction while the reaction(gun cocked backwards) acts in the opposite direction. Similarly for the club and the golf ball, the force exerted on the golf ball by the club will create an opposing force due to the effect of the golf ball on the club itself.
With the switch open, there's no current in the circuit, and therefore no voltage drop across any of the dissipative elements (the resistor or the battery's internal impedance). So the entire battery voltage appears across the switch, and the voltmeter reads 12.0V .
