According to Newton's Second Law, the force of the club hitting the golf ball will cause it to accelerate. At the moment of impa
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Answer:
a) the magnitude of r is 184.62
b) the direction is 37.74° south of the negative x-axis
Explanation:
Given the data in the question;
as illustrated in the image blow;
To find the the magnitude of r, we will use the Pythagoras theorem
r² = y² + x²
r = √( y² + x²)
we substitute
r = √((-113)² + (-146)²)
r = √(12769 + 21316 )
r = √(34085 )
r = 184.62
Therefore, the magnitude of r is 184.62
To find its direction, we need to find ∅
from SOH CAH TOA
tan = opposite / adjacent
tan∅ = -113 / -146
tan∅ = 0.77397
∅ = tan⁻¹( 0.77397 )
∅ = 37.74°
Therefore, the direction is 37.74° south of the negative x-axis
The final speed of the block after the collision with the obstacle is .
Further Explanation:
Given:
The mass of the block is .
The initial momentum of the block is .
The impulse imparted by the obstacle is .
Concept:
The block is sliding towards east and the impulse imparted by the obstacle is towards the obstacle is towards west on the block. It means that the impulse exerted by the obstacle will reduce the momentum of the block.
According to the impulse momentum theorem, the rate of change of momentum of the body is equal to the impulse imparted to the body.
The expression for the impulse momentum theorem is.
…… (1)
Substitute for
and
for
in equation (1).
The final momentum of the block can be expressed as:
…… (2)
Substitute for
and
for
in equation (2).
Thus, the final speed of the block after the collision with the obstacle is .
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Answer Details:
Grade: High School
Chapter: Impulse-momentum theorem
Subject: Physics
Keywords: Impulse, imparted, obstacle, speed, momentum, the obstacle, impulse-momentum theorem, frictionless surface, speed of block after collision.