Roughness of the surface and weight of the object.
Answer:
molecules C6H12O6 = 2.674 E22 molecules.
Explanation:
from periodic table:
⇒ molecular mass C6H12O6 = ((6)(12.011)) + ((12)(1.008)) + ((6)(15.999))
⇒ Mw C6H12O6 = 180.156 g/mol
⇒ mol C6H12O6 = (8.00 g)(mol/180.156 g) = 0.0444 mol C6H12O6
∴ mol ≡ 6.022 E23 molecules
⇒ molecules C6H12O6 = (0.0444 mol)(6.022 E23 molecules/mol)
⇒ molecules C6H12O6 = 2.674 E22 molecules
I believe the end result is still 83 moles since there is never an amount of sulfur atoms added to the initial amount, but rather oxygen and water is repeatedly added to it. To find it's weight, first find the molar mass of H2SO4:
H2 + S + O4 = 2.00 + 32.1 + 64.0 = 98.1 g/mol
and mass = (98.1 g/mol)(83 mol) = 8142.3 g
rounded to 8.1 x 10^3 g assuming 100% yield?
Answer:
Percent error = 5.6%
Explanation:
Given data:
Measured value of density by students = 2.85 g/cm³
Accepted density of aluminium = 2.70 g/cm³
Percent error = ?
Solution:
Formula:
Percent error = [ Measured value - accepted value / accepted value ]× 100
Now we will put the values in formula:
Percent error = [ 2.85 g/cm³ - 2.70 g/cm³ / 2.70 g/cm³ ]× 100
Percent error = [0.15/2.70 g/cm³ ] × 100
Percent error = 0.056× 100
Percent error = 5.6%
Answer:
a., c.
Explanation:
P1V1 =P2V2 is true when T is constant and number of moles n is constant also.
