We want to use this primary leaving group on this primary starting material because it will give us a greater yield and say, if we were to use a secondary reagent in place of this primary.
Now we've moved on from our fundamentals. So we have our starting material and we have That's our beautiful sec futile ether. So now that we've written out are starting material, we can take a thing about where exactly some reactivity may happen. So, for example, could start out with an alcohol that looks as the following. This is a secondary alcohol you can see. So now we need to take a look at some of alcohol.
So now we need to think about our alcohol. Hey, light again. Well, we'll have a hey light. That's a very good leaving group. So we need alcohol. So for example, so now we have a primary structure here, So this will undergo and s and two reaction due to the lacking of hysteric hindrance. Formal negative charge attacks that electrical it carbon bro.
Learn more about Alcohol here-
brainly.com/question/14229343
#SPJ4
Answer:
σ = 4.998 E-4 C/m²
Explanation:
- 1 Coulomb (C) ≡ 6.241509 E18 electrons (e)
∴ # elect = 6.24 E14 elect
charge (Q):
⇒ Q = (6.24 E14 elect)/( 1 C /6.241509 E18 elect) = 9.998 E-5 C
charge density (σ):
∴ surface area (S) = 0.2 m²
⇒ σ = ( 9.998 E-5 C ) / ( 0.2 m²)
⇒ σ = 4.998 E-4 C/m²
No. Although two such atoms are essentially chemically identical (they will chemically react in the same way), they are not completely identical.
Explanation:
The transuranium elements are produced by the capture of neutrons
<u>Hope</u><u> </u><u>it</u><u> </u><u>will</u><u> </u><u>help</u><u> </u><u>you</u>
