Answer: 44g
Explanation: The formular for finding Moles is ;
Moles = Mass / Molar Mass or Formular Mass.
Base on this question; Moles = 10, Mass = 440g, and Formular Mass = ?
Making 'Formular Mass', subject of the formular; we thus have;
Formular mass = Mass / Moles = 440/ 10 = 44g
According to law of definite proportion, for a compound, elements always combine in fixed ratio by mass.
The formula of compound remains the same, let it be a_{x}b_{y} where, a and b are two different elements.
Since, the ratio of mass remains the same , calculate the ratio of masses of element a and b in both cases
\frac{a}{b}=\frac{15}{35}=\frac{10}{y}
rearranging,
y=\frac{10\times 35}{15}=23.3
Thus, mass of b produced will be 23.3 g.
If a metal is less reactive than carbon, it can be extracted from its oxide by heating with carbon. The carbon displaces the metal from the compound, and removes the oxygen from the oxide. This leaves the metal.
Element on the right side of the periodic table differ from the elements on the left side in that elements on the <em>right side are non metallic and tends to be gases at room temperature.</em>
<em> </em><u>Explanation</u>
In the periodic table there element in the right side , left side and those which are in between.
- Example of element in the right side is fluorine chlorine, neon, Argon among others.
- This element have higher effective nuclear charges and stabilize electrons more effectively.
- there electrostatic intermolecular forces are generally weak therefore they exist in liquid or gaseous state.
Answer:
500g because 300g is less dense than 500g its kinda like a weight
Explanation:
i
