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3 years ago

When a ray of light passes at an angle to the normal from one material into another material in which its speed is higher?

1 answer:

4 0

I think your talking about refraction and if so the first medium it existed in before entering the second usually has the higher speed especially it the first medium is less denser than the second

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De onde veio o dinheiro para financiar a indústria no Brasil a partir de 1930?

liq [111]

Answer: Descomponiendo los ingresos de Brasil, encontramos que se derivan de los siguientes tres sectores: agricultura, industria y servicios. Según estimaciones de 2014, el 5,8% de los ingresos de Brasil provino de la agricultura, el 23,8% de la industria y el 70,4% de los servicios.Durante las décadas de 1940 y 1950, el gobierno brasileño comenzó a construir acerías, refinerías de petróleo y represas hidroeléctricas. ... Brasil se encuentra entre las principales naciones industriales del mundo, debido al gasohol.

Explanation:

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3 years ago

How do electric motors create movement?

melomori [17]

Answer:

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7 0

3 years ago

Walt ran 5 km in 25 minutes going east to what was his average velocity

goldenfox [79]

distance d = 5 km = 5 x 1000 m = 5000 m

time taken = 25 minute = 25 x 60 sec = 1500 sec

average velocity V = d/t

V = 5000/1500

V = 3.33 m/s towards east

3 0

3 years ago

Read 2 more answers

An isotope undergoes radioactive decay by emitting radiation that has no mass. What other characteristic does the radiation have

vitfil [10]

Other characteristic of radiation is the presence of positive and negative charge.

<h3 /><h3>What other characteristic does the radiation have?</h3>

Positive or negative charge are the other characteristic that is present in the radiation. Beta radiation have negative charge while on the other hand, alpha radiation have positive charge.

So we can conclude that other characteristic of radiation is the presence of positive and negative charge.

Learn more about radiation here: brainly.com/question/893656

#SPJ1

4 0

2 years ago

A motorcycle daredevil plans to ride up a 2.0-m-high, 20° ramp, sail across a 10-m-wide pool filled with hungry crocodiles, and

il63 [147K]

Answer:

He becomes a croco-dile food

Explanation:

From the question we are told that

The height is h = 2.0 m

The angle is $\theta = 20^o$

The distance is $w = 10m$

The speed is $u = 11 m/s$

The coefficient of static friction is $\mu = 0.02$

At equilibrium the forces acting on the motorcycle are mathematically represented as

$ma = mgsin \theta + F_f$

where $F_f$ is the frictional force mathematically represented as

$F_f =\mu F_x =\mu mgcos \theta$

where $F_x$ is the horizontal component of the force

substituting into the equation

$ma = mgsin \theta + \mu mg cos \theta$

$ma =mg (sin \theta + \mu cos \theta )$

making a the subject of the formula

$a = g(sin \theta = \mu cos \theta )$

substituting values

$a = 9.8 (sin(20) + (0.02 ) cos (20 ))$

$= 3.54 m/s^2$

Applying " SOHCAHTOA" rule we mathematically evaluate that length of the ramp as

$sin \theta = \frac{h}{l}$

making $l$ the subject

$l = \frac{h}{sin \theta }$

substituting values

$l = \frac{2}{sin (20)}$

$l = 5.85m$

Apply Newton equation of motion we can mathematically evaluate the final velocity at the end of the ramp as

$v^2 =u^2 + 2 (-a)l$

The negative a means it is moving against gravity

substituting values

$v^2 = (11)^2 - 2(3.54) (5.85)$

$v= \sqrt{79.582}$

$= 8.92m/s$

The initial velocity at the beginning of the pool (end of ramp) is composed of two component which is

Initial velocity along the x-axis which is mathematically evaluated as

$v_x = vcos 20^o$

substituting values

$v_x = 8.92 * cos (20)$

$= 8.38 m/s$

Initial velocity along the y-axis which is mathematically evaluated as

$v_y = vsin\theta$

substituting values

$v_y = 8.90 sin (20)$

$= 3.05 m/s$

Now the motion through the pool in the vertical direction can mathematically modeled as

$y = y_o + u_yt + \frac{1}{2} a_y t^2$

where $y_o$ is the initial height,

$u_y$ is the initial velocity in the y-axis

$a_y$ is the initial acceleration in the y axis with a constant value of ( $g = 9.8 m/s^2$ )

at the y= 0 which is when the height above ground is zero

Substituting values

$0 = 2 + (3.05)t - 0.5 (9.8)t^2$

The negative sign is because the acceleration is moving against the motion

$-(4.9)t^2 + (2.79)t + 2m = 0$

Solving using quadratic formula

$\frac{-b \pm \sqrt{b^2 -4ac} }{2a}$

substituting values

$\frac{-3.05 \pm \sqrt{(3.05)^2 - 4(-4.9) * 2} }{2 *( -4.9)}$

$t = \frac{-3.05 + 6.9}{-9.8} \ or t = \frac{-3.05 - 6.9}{-9.8}$

$t = -0.39s \ or \ t = 1.02s$

since in this case time cannot be negative

$t = 1.02s$

At this time the position the motorcycle along the x-axis is mathematically evaluated as

$x = u_x t$

x $=8.38 *1.02$

$x =8.54m$

So from this value we can see that the motorcycle would not cross the pool as the position is less that the length of the pool

7 0

3 years ago