<span>a)
</span>First order
in A and zero order in B
<span>ln [A]
= (ln 0.1) (2) + ln Ao = ln 0.01 + ln Ao = ln 0.01 Ao = 1.0% of A will remain</span>
<span>b)
</span>First
order in A and first order in B
<span>1/[A] – 1/[A]0= kt where t+=1 and k=9</span>
[A]/[A]=1/19=0.053=5.3%
<span>c)
</span>Zero
order in both A and B
<span>[A]0-[A] = kt</span>
Then at 2
hours [A]=0 All of it has reacted.
<span> </span>
Answer:
9.17 atm
Explanation:
To find the new pressure of the gas, you need to use the following manipulated formula:
P₁V₁ / T₁ = P₂V₂ / T₂
In this formula,
P₁ = initial pressure (atm) P₂ = new pressure (atm)
V₁ = initial volume (L) V₂ = new volume (L)
T₁ = initial temperature (K) T₂ = new temperature (K)
Because you have been given values for all of the variables except for the new pressure, you can substitute them into the equation and simplify.
P₁ = 4.0 atm P₂ = ? atm
V₁ = 5.5 L V₂ = 2.0 L
T₁ = 300 K T₂ = 250 K
P₁V₁ / T₁ = P₂V₂ / T₂ <----- Given formula
(4.0 atm)(5.5 L) / (300 K) = P₂(2.0 L) / (250 K) <----- Insert variables
0.073333 = P₂(2.0 L) / (250 K) <----- Simplify left side
18.33333 = P₂(2.0 L) <----- Multiply both sides by 250
9.17 = P₂ <----- Divide both sides by 2.0
Answer:
1.2 M
Explanation:
If you use the dilution equation (M1V1=M2V2), you end up with (50)(12)=(500)(M2), and when you solve for M2 you get 1.2 M.
Answer:
T°fussion of solution is -18°C
Explanation:
We have to involve two colligative properties to solve this. Let's imagine that the solute is non electrolytic, so i = 1
First of all, we apply boiling point elevation
ΔT = Kb . m . i
ΔT = Boiling T° of solution - Boiling T° of pure solvent
Kb = ebuliloscopic constant
105°C - 100° = 0.512 °C kg/mol . m . 1
5°C / 0.512 °C mol/kg = m
9.7 mol/kg = m
Now that we have the molality we can apply, the Freezing point depression.
ΔT = Kf . m . i
Kf = cryoscopic constant
0° - (T°fussion of solution) = 1.86 °C/m . 9.76 m . 1
- (1.86°C /m . 9.7 m) = T°fussion of solution
- 18°C = T°fussion of solution
Answer:
Double Displacement Reaction
Explanation:
A double displacement reaction is a type of chemical reaction in which the reactant ions exchange places to form new products. Usually, a double displacement reaction results in precipitate formation.
