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antoniya [11.8K]
3 years ago
5

How many moles of sodium would be needed to react with 3.82 moles of oxygen

Chemistry
2 answers:
STALIN [3.7K]3 years ago
8 0
You would need 13.5 moles of sodium
Diano4ka-milaya [45]3 years ago
3 0
I think it would be 13.5
Hope this helps

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Is krypton a non-reactive, highly reactive, or radioactive?​
Julli [10]

Answer:

Krypton does not react with anything, but it reacts with fluorine gas

Explanation:

7 0
2 years ago
Calculate the concentration of the following solution in mol/dm3 0.1 moles of NaCl in 200 cm3
taurus [48]
1 cm ^{3} = 0.001 dm ^{3}. Therefore 200 cm ^{3} = 0.2 dm ^{3}. Molarity = \frac{number of moles of NaCl}{volume of the solution} =  \frac{0.1}{0.2} = 0.5 mol/dm^{3}. Hope this helps.
8 0
3 years ago
Volume occupied 3.52x10^32 moluchles<br>of Mathane (CH4)<br>1) At STP​
Naddika [18.5K]

Answer:

volume = 13097674418.528dm³

Explanation:

n = (3.52)*10^32/(6.02)*10^23)

n = (584717607.97)

n = volume /molar volume

molar volume at stp = 22.4dm³

volume= 584717607.97 x 22.4

volume = 13097674418.528dm³

6 0
2 years ago
How many 325mg aspirin tablets can be made from 3628 grams of aspirins ? Need an answer by tonight it’s getting late .
krek1111 [17]

I took the mg and converted it to grams. That gave me .325 grams. I took that and multiplied that by 3628 grams. If I did my math correctly, the answer would be 1179.1. Rounded up, that would be 1179 aspirin tablets.   Hope this helps. :)

4 0
3 years ago
If is found that 24.68 mL of .1165 M NaOH is needed to titrate .2931 g of an unknown acid to the phenolphthalein end point. Calc
Lemur [1.5K]

Answer: The equivalent mass of the acid is 83.16 grams

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}  

Molarity of NaOH solution = 0.1165 M

Volume of NaOH solution = 24.68 mL = 0.02468 L

Putting values in equation 1, we get:

\text{Moles of} NaOH={0.1165M}\times{0.02468L}=2.875\times 10^{-3}moles=2.875\times 10^{-3}geq    

( as acidity of NaOH is 1)

For end point:  gram equivalents of acid =  gram equivalents of base = 2.875\times 10^{-3}

Mass of acid=gram equivalents\times {\text {Equivalent mass}}

0.2391=2.875\times 10^{-3}\times {\text {Equivalent mass}}

{\text {Equivalent mass}}=83.16g

Thus equivalent mass of the acid is 83.16 grams

5 0
3 years ago
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