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antoniya [11.8K]
3 years ago
5

How many moles of sodium would be needed to react with 3.82 moles of oxygen

Chemistry
2 answers:
STALIN [3.7K]3 years ago
8 0
You would need 13.5 moles of sodium
Diano4ka-milaya [45]3 years ago
3 0
I think it would be 13.5
Hope this helps

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A red blood cell is placed into each of the following solutions. Indicate whether crenation, hemolysis, or neither will occur.
krok68 [10]

Answer:

Following are the responses to the given choices:

Explanation:

  • The RBC crenation is implied through NaCl by 2,67 percent(m/v) because that solution becomes hypertonic to RBC because of the water within the RBC that passes externally towards the outskirts. RBC thus shrinks.
  • 1.13% (m/v), because the low concentration or osmotic that all this solution shows is hypotonic regarding RBC because of the water which has reached the resulting swelling in RBC.
  • Distilled H2 implies hemolytic distillation.
  • Glucose is indicated by crenation at 8.69 percent (m/v).
  • 5.0% (m/v) glucose and 0.9% (m/v) (Crenation is indicated by NaCl.v)
3 0
3 years ago
The boiling points for the homonuclear diatomic molecules in the halogen family are 85 K, 238 K, 332 K, 457 K and 610 K. Which s
patriot [66]

Answer:

Cl_{2} has boiling point of 238 K

Explanation:

Boiling point depends on different intermolecular force such as molecular wight, dipole-dipole attraction force, hydrogen bonding, ionic attraction force.

Homonuclear diatomic molecules are covalent non-polar molecules and thereby free from dipole-dipole attraction force, hydrogen bonding and ionic interaction forces.

Hence, boiling point of homonuclear diatomic molecules depends solely on molecular weight.

We know, higher the molecular weight of a molecule, higher will be its boiling point. This phenomenon can be realized in terms of increasing london dispersion force with increase in molecular weight.

Decreasing order of molecular weight of halogen molecules :

I_{2} > Br_{2} > Cl_{2} > F_{2}

So, decresing order of boiling point of halogen molecules:

I_{2} > Br_{2} > Cl_{2} > F_{2}

Hence Cl_{2} has boiling point of 238 K

4 0
3 years ago
3. Burns from boiling water can be severe, caused by the transfer of energy from the boiling water to the
Free_Kalibri [48]

Answer:

Q = 3937.56  J

Explanation:

Heat transferred due to change in temperature is given by :

Q=mc\Delta T

c is the specific heat of water, c=4.18 J/g-°C

We have, m = 15 g, T_i=100^{\circ} C\ \text{and}\ T_f=37.2^{\circ} C

So,

Q=15\times 4.18\times (37.2-100)\\Q=-3937.56\ J

Hence, 3937.56  J of heat is transferred.

8 0
3 years ago
Can someone please help me understand this?
Nataliya [291]

Answer:

French physicist Jacques Charles (1746-1823) studied the effect of temperature on the volume of a gas at constant pressure. Charles's Law states that the volume of a given mass of gas varies directly with the absolute temperature of the gas when pressure is kept constant. The absolute temperature is temperature measured with the Kelvin scale. The Kelvin scale must be used because zero on the Kelvin scale corresponds to a complete stop of molecular motion.

alt

Figure 11.5.1: As a container of confined gas is heated, its molecules increase in kinetic energy and push the movable piston outward, resulting in an increase in volume.

Mathematically, the direct relationship of Charles's Law can be represented by the following equation:

V

T

=k

As with Boyle's Law, k is constant only for a given gas sample. The table below shows temperature and volume data for a set amount of gas at a constant pressure. The third column is the constant for this particular data set and is always equal to the volume divided by the Kelvin temperature.

Explanation:

PLEASS MARK ME AS BRAINLIEST ANSWER

4 0
3 years ago
Convert 533 cm/s to units of meters per minute. Show the unit analysis by dragging the conversion factors into the unit‑factor s
lukranit [14]

Answer:

319.8 m/min

Explanation:

533 cm/s

We can convert 533 cm/s to m/min by doing the following:

First, we shall convert 533 cm/s to m/s. This can be obtained as illustrated below:

Recall:

100 cm/s = 1 m/s

Therefore,

533 cm/s = 533 cm/s /100 cm/s × 1 m/s

533 cm/s = 5.33 m/s

Finally, we shall convert 5.33 m/s to m/min. This can be obtained as follow:

1 m/s = 60 m/min

Therefore,

5.33 m/s = 5.33 m/s / 1 m/s × 60 m/min

5.33 m/s = 319.8 m/min

Therefore, 533 cm/s is equivalent to 319.8 m/min

8 0
3 years ago
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