<span>Newton established his three laws of motion to understand the motion of objects in a systematic way [ same thing as all Scientists did for human's curiosity ].
His three laws of motion are as follows:
First Law: - </span><span> An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.
Second Law: - </span><span> The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
Third Law: - </span><span>For every action, there is an equal and opposite reaction
Hope this helps!</span>
It is not possible to explain the interaction of the rod and pieces of paper as a gravitational interaction.
<h3>What is Gravitational interaction?</h3>
This is defined as the interaction between a particle or body resulting from their mass. This type of interaction is usually weak and occurs in all distances possible.
It is not gravitational interaction, because the rod attracts paper only against the gravitational force of the earth and there is no attraction between both bodies under a different condition.
This is therefore the reason why it is not possible to explain the interaction of the rod and pieces of paper as a gravitational interaction.
Read more about Gravitational interaction here brainly.com/question/25624188
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A common example of radiation would have to be sunlight
The total gauge pressure at the bottom of the cylinder would
simply be the sum of the pressure exerted by water and pressure exerted by the
oil.
The formula for calculating pressure in a column is:
P = ρ g h
Where,
P = gauge pressure
ρ = density of the liquid
g = gravitational acceleration
h = height of liquid
Adding the two pressures will give the total:
P total = (ρ g h)_water + (ρ g h)_oil
P total = (1000 kg / m^3) (9.8 m / s^2) (0.30 m) + (900 kg /
m^3) (9.8 m / s^2) (0.4 - 0.30 m)
P total = 2940 Pa + 882 Pa
P total = 3,822 Pa
Answer:
The total gauge
pressure at the bottom is 3,822 Pa.
