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arlik [135]
2 years ago
11

What is the most significant chemical difference between triacylglycerols and glycerophospholipids that leads to their different

functions?
Chemistry
1 answer:
satela [25.4K]2 years ago
5 0

Answer:

Triacylglycerols (triglycerides) are non-polar or hydrophobic molecules

Glycerophospholipids (phosphoglycerides) are polar or hydrophilic

Explanation:

Triacylglycerides (TGs) are esters synthesized by the esterification of three molecules of glycerol and fatty acid, and this is essentially by the replacement of the three hydroxyl groups on glycerol with three fatty acids. This removes the hydrophilic property from the glycerol molecule hence TGs are only soluble in non-polar solvents like alcohol and benzene, and TGs are therefore the storage forms of fats in adipose tissues.

Glycerophospholipids are formed by the addition of two hydrophobic fatty acid groups and one phosphoric acid (phosphate group) to glycerol (alcohol) leaving a hydrophilic head (phosphate end) and a hydrophobic tail (fatty acid ends). This amphipathic property of this molecule makes it a suitable molecule for membrane structures, especially of cells (lipid bi-layer), with an arrangement where the hydrophilic side interacts with the aqueous environment, while the hydrophobic side makes contact with the non-aqueous environment.

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A copper cylinder, 12.0 cm in radius, is 44.0 cm long. If the density of commoner is 8.90 g/cm3, calculate the mass in grams of
inna [77]

The mass of the copper cylinder is 177065.856g

Given:

Radius of the copper cylinder R=12cm

Height of the copper cylinder H=44cm

Density of the cylinder=8.90 \frac{g}{c m^{3}}

To find:

Mass of the copper cylinder

<u>Step by Step by explanation:</u>

Solution:

According to the formula, Mass can be calculated as

\rho=\frac{m}{v} and from this

m=\rho \times v

Where, m=mass of the cylinder

\rho =density of the cylinder

v=volume of the cylinder

And also cylinder is provided with radius and height value.

So volume of the cylinder is calculated as

v=\pi r^{2} h

Where \pi=3.14

r=radius of the cylinder=12cm

h=height of the cylinder=44cm

Thus, v=3.14 \times 12^{2} \times 44

v=3.14 \times 144 \times 44

v=19895.04 \mathrm{cm}^{3}

And we know that, m=\rho \times v

Substitute the known values in the above equation we get

m=8.90 \times 19895.04  

m=177065.856g or 177.065kg

Result:

Thus the mass of the copper cylinder is 177065.856g

4 0
3 years ago
Textbook mass 2000 grams volume 4000cm3 density
PIT_PIT [208]
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3 years ago
True or false The atomic number of an element is always more than the mass number of that element.
Veseljchak [2.6K]
The sentence is true
8 0
3 years ago
Scientists use _____ as chemical symbols.<br><br> dots<br> letters<br> shapes<br> lines
defon

Answer:

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Explanation:

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3 years ago
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Analysis of an athletes urine found the presence of a compound with a molar mass of 312 g/mol. How many moles of this compound a
rewona [7]
<h3>Answer:</h3>

= 5.79 × 10^19 molecules

<h3>Explanation:</h3>

The molar mass of the compound is 312 g/mol

Mass of the compound is 30.0 mg equivalent to 0.030 g (1 g = 1000 mg)

We are required to calculate the number of molecules present

We will use the following steps;

<h3>Step 1: Calculate the number of moles of the compound </h3>

Moles=\frac{mass}{molar mass}

Therefore;

Moles of the compound will be;

=\frac{0.030}{312g/mol}

      = 9.615 × 10⁻5 mole

<h3>Step 2: Calculate the number of molecules present </h3>

Using the Avogadro's constant, 6.022 × 10^23

1 mole of a compound contains 6.022 × 10^23  molecules

Therefore;

9.615 × 10⁻5 moles of the compound will have ;

= 9.615 × 10⁻5 moles × 6.022 × 10^23  molecules

= 5.79 × 10^19 molecules

Therefore the compound contains 5.79 × 10^19 molecules

5 0
3 years ago
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