The given elements put into an equation using their symbols are as follows:
Pb +

=

+ Ag
Since there are 2 Pb on the right side of the equation, you would change the coefficient of Pb on the left side to 2:
2Pb +

=

+ Ag
Since there are 2 Acetate on the right side of the equation, you would change the coefficient of Silver Acetate on the left side to 2:
2Pb +

=

+ Ag
Now there are 2 Silver on the left side, so you change the coefficient of Silver on the right side to 2:
2Pb +

=

+ 2Ag
That is your final equation
The coefficients are 2 + 2 = 1 + 2
Answer:
Option-B (2-methylpropene)
Explanation:
The reaction scheme is attached below,
In first step the alkene acts a nucleophile and adds H⁺ across double bond yielding a stable tertiary carbocation.
In the second step the oxygen atom of methanol acts as nucleophile and attacks the positive charge carrying carbon atom resulting in the formation of t-butyl methyl ether.
Answer:
Formula Weight of gas sample = 20.1 g/mole => Neon (Ne)
Explanation:
Use Ideal Gas Law formula to determine formula weight and compare to formula weights of answer choices.
PV = nRT = (mass/fwt)RT => fwt = (mass/Volume)RT = Density x R x T
Density = 0.900 grams/L
R = 0.08206 L·atm/mole·K
T = 0.00°C = 273Kfwt = (0.900g/L)(0.08206L·atm/mole·K )(273K)
= 20.1 g/mol => Neon (Ne)
Its all of the above.
- I took the test and mine is correct.
It is always the same as it was before the collision because there is no outside forces it is left with the same amount of energy throughout thee collision.