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Vesnalui [34]
3 years ago
8

Help me! Who ever gets to answer and has the best answer gets brainliest

Chemistry
2 answers:
Troyanec [42]3 years ago
7 0

Answer:

Fires - These consume fuel and covert chemical energy stored in that fuel into thermal, light and sound energy

Decay - The breakdown of dead plants and animals produces thermal energy

Earth - Thermal energy comes from deep inside and is called geothermal energy

Explanation:

Fires, when you burn wood, you convert chemical energy from the wood into thermal (warmth from the fire), light (glow from the fire), sound (crackling sound of wood burning)

Decay - I can't explain that one to you but there are power plants that use decomposition to produce energy

Earth - Beneath the crust there is the mantle, which consists of molten rock which produces a lot of thermal energy. This can be seen in geysers, where the molten rock heats water and hot water can burst out of the surface. Applies to hot springs too

gayaneshka [121]3 years ago
6 0

Answer:

Decay-the breakdown of dead plants..

Earth- thermal energy comes from deep inside...

Fires- these consume feul...

Explanation:

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What is the volume of 1.4 mol of nitrogen gas at STP?
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31.36 Liters

Explanation:

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A certain reaction has an activation energy of 25.88 kJ/mol. At what Kelvin temperature will the reaction proceed 6.00 times fas
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5 0
2 years ago
If 20.0 g of NaOH is added to 0.750 L of 1.00 M Cd(NO₃)₂, how many grams of Cd(OH)₂ will be formed in the following precipitatio
bulgar [2K]

Answer:

m_{Cd(OH)_2}=36.6 gCd(OH)_2

Explanation:

Hello.

In this case, for the given chemical reaction, in order to compute the grams of cadmium hydroxide that would be yielded, we must first identify the limiting reactant by computing the yielded moles of that same product, by 20.0 grams of NaOH (molar mass = 40 g/mol) and by 0.750 L of the 1.00-M solution of cadmium nitrate as shown below considering the 1:2:1 mole ratios respectively:

n_{Cd(OH)_2}^{by\ NaOH}=20.0gNaOH*\frac{1molNaOH}{40gNaOH} *\frac{1molCd(OH)_2}{2molNaOH} =0.25molCd(OH)_2\\\\n_{Cd(OH)_2}^{by\ Cd(NO_3)_2}=0.750L*1.00\frac{molCd(NO_3)_2}{L}*\frac{1molCd(OH)_2}{1molCd(NO_3)_2}  =0.75molCd(OH)_2

Thus, since 20.0 grams of NaOH yielded less of moles of cadmium hydroxide, NaOH is the limiting reactant, therefore the mass of cadmium hydroxide (molar mass = 146.4 g/mol) is:

m_{Cd(OH)_2}=0.25molCd(OH)_2*\frac{146.4gCd(OH)_2}{1molCd(OH)_2} \\\\m_{Cd(OH)_2}=36.6 gCd(OH)_2

Best regards.

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3 years ago
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yawa3891 [41]
The answer is 0.375 mol of silver chromate
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3 years ago
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