Answer:
112.92 s.
Explanation:
Let M₁ be the molar mass of N₂O
Let t₁ be the time taken for N₂O to effuse.
Let M₂ be the molar mass of I₂
Let t₂ be the time taken for I₂ to effuse.
Molar mass (M₁) of N₂O = (14×2) + 16 = 28 + 16 = 44 g/mol
Time (t₁) of effusion of N₂O = 47 s
Molar mass (M₂) of I₂ = 127 × 2 = 254 g/mol
Time (t₂ ) of effusion of I₂ =?
The time take for the same amount of I₂ to effuse can be obtained as follow:
t₂/t₁ = √(M₂/M₁)
t₂/47 = √(254 / 44)
Cross multiply
t₂ = 47 × √(254 / 44)
t₂ = 112.92 s
Therefore, it will take 112.92 s for the same amount of I₂ to effuse.
Answer:
11x³ – 2x² + 3x + 11
Explanation:
From the question given above:
We are to find the sum of:
4x³ + 2x² – 4x + 3 and 7x³ – 4x² + 7x + 8
To add the above polynomials together we must recognise that we can only add like terms together. The sum of the above polynomials can be obtained as follow:
. 4x³ + 2x² – 4x + 3
+ 7x³ – 4x² + 7x + 8
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
= 11x³ – 2x² + 3x + 11
Thus, the sum of 4x³ + 2x² – 4x + 3 and 7x³ – 4x² + 7x + 8 is 11x³ – 2x² + 3x + 11
Answer:
The answer to your question is: 3.745 x 10 ²³ atoms
Explanation:
Data
density = 8.96 g/cm³
mass = 29.54 g
atomic radius = 1.28 A° 1.28 x 10⁻¹⁰ m
Volume of a cube
density = mass / volume
volume = mass / density
volume = 29.54 / 8.96
volume = 3.29 cm³
Volume of a copper atom
volume = (4/3) πr³
volume = (4/3) π (1.28 x 10 ⁻⁸)³
= 8.784 x 10 ⁻²⁴ cm³
Number of atoms = 3.29 cm³ / 8.784 x 10 ⁻²⁴ cm³
= 3.745 x 10 ²³ atoms
