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3 years ago

Only 5 questions plz answer.

Physics

2 answers:

Masja [62]3 years ago

6 0

Question 18: a
question 19: b
question 20: c

makvit [3.9K]3 years ago

4 0

18: A
19:B
20:C
:))))))))))())))))))))))))))));):$:$:$:$:$:$

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What is the impact force on a 0.5 kg object if it falls 3 meters and hits a carpeted floor at 8 m/s, stopping in 0.10 seconds?

Cerrena [4.2K]

the I'm pact force of 0.5 is lol u guys go and study why r u asking answers

4 0

3 years ago

Its mass is 20 grams, and its density is 7.87 g/cm3. What’s the larger cube’s volume?

Alik [6]

Volume = mass / density
Volume = 20 / 7.87
Volume = 2.54 (2 s.f)

3 0

3 years ago

A 20 kg child is on a swing that hangs from 3.0-m-long chains. what is her maximum speed if she swings out to a 45° angle?

fomenos

The solution for this problem is:

Remember that this doesn’t depend on the mass of the child.

E = T + U = constant
E (maximum height) = T + U =U = mgh = mg[r - r· cos (Θ)]

E (bottom height) = T + U = T = ½mv² = mg[r - r · cos (Θ)]

v² = 2g[r – r · cos (Θ)]

v = √ (2g[r-r·cos(Θ)])

= √(2(9.8)[3 – 3 · cos (45°)])

= 4.15 m/s or 15 kph

4 0

4 years ago

Read 2 more answers

Ideal gases are often studied at standard ambient temperature and pressure (satp). The international union of pure and applied c

11Alexandr11 [23.1K]

This problem provides information about the pressure and temperature ideal gases are studied at. The answer to the questions are that all molecules have the same density, 2.43x10²⁵ mol/m³ and 2.43x10¹⁹ mol/cm³.

<h3>Idela gases</h3>

In science, we can start studying gases with the concept of ideal gas, as they do not collide one to another and are assumed to be perfect spheres with no relevant interactions.

In such a way, one can conclude that the <u>number density of all ideal gasses at SATP is the same</u>, as they are assumed to be perfect spheres with equal volumes per molecule.

Moreover, when calculating the number of molecules per cubic meter, one must use the ideal gas equation as:

$PV=nRT\\\\\frac{N}{V}= \frac{P*N_A}{RT}$

And plug in the numbers we are given:

$\frac{N}{V}= \frac{100kPa*\frac{1000Pa}{1kPa}*6.022x10^{23}molec/mol}{8.314\frac{Pa*m^3}{mol*K}*298K}=2.43x10^{25}molec/m^3$

Lastly, we can calculate the molecules per cubic centimeter by performing the following conversion:

$2.43x10^{25}\frac{molec}{m^3}*(\frac{1m}{100cm} )^3\\ \\=2.43x10^{19}\frac{molec}{cm^3}$

Learn more about ideal gases: brainly.com/question/26450101

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3 years ago

When the rubber sheet is pulled down, the volume of the bell jar is ____________ and the pressure in the bell jar is ___________

Makovka662 [10]

Answer:

increases, decreases, respiration

8 0

2 years ago