Answer: The standard entropy of vaporization of ethanol is 0.275 J/K
Explanation:
Using Gibbs Helmholtz equation:
For a phase change, the reaction remains in equilibrium, thus 
Given: Temperature = 285.0 K
Putting the values in the equation:
Thus the standard entropy of vaporization of ethanol is 0.275 J/K
Answer:
The answer is evaporation
Answer:
1.375%
Explanation:
Percent Error = measured value - accepted value/ accepted value x 100
Measured Value: 15.78
Accepted Value: 16.00
Work:
* 100
* 100 = -1.375
You cannot have a negative percentage. Therefore the answer is 1.375%
(the heat bomb calorimeter gained)=(the heat material A gave)
r.h.s=25.57 kJ/⁰C * (26.80-24.33)= 63.16 kJ
2.741g of material A made 63.16kJ
the heat of combustion per gram = 63.16/2.741 kJ/g =24.04kJ/g
