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3 years ago

Will mark as brainlist for only correct answer

Physics

1 answer:

ozzi3 years ago

5 0

Answer:

4 cm/s

Explanation:

Wave speed is the distance a wave travels in a given amount of time, such as the number of meters it travels per second. Wave speed (and speed in general) can be represented by the equation:

Speed = Distance/Time

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You fire a paintball from a paintball gun straight up into the air at 25.0 m/s. What is the ball velocity at the higher point th

iVinArrow [24]

Given :

You fire a paintball from a paintball gun straight up into the air at 25.0 m/s.

To Find :

What is the ball velocity at the higher point that the ball reaches.

Solution :

We know, when ball is moving upward acceleration due to gravity is applied downward.

So, the ball will decelerate and when ball reaches maximum height its velocity will become zero.

Therefore, ball velocity is 0 m/s at maximum height.

Hence, this is the required solution.

5 0

3 years ago

A capacitor with initial charge q0 is discharged through a resistor. a) In terms of the time constant τ, how long is required fo

-BARSIC- [3]

Answer:

It would take $\tau(\ln 9 - \ln 8)$ time for the capacitor to discharge from $q_0$ to $\displaystyle \frac{8}{9} \, q_0$ .

It would take $\tau(\ln 9 - \ln 7)$ time for the capacitor to discharge from $q_0$ to $\displaystyle \frac{7}{9}\, q_0$ .

Note that $\ln 9 = 2\,\ln 3$ , and that $\ln 8 = 3\, \ln 2$ .

Explanation:

In an RC circuit, a capacitor is connected directly to a resistor. Let the time constant of this circuit is $\tau$ , and the initial charge of the capacitor be $q_0$ . Then at time $t$ , the charge stored in the capacitor would be:

$\displaystyle q(t) = q_0 \, e^{-t / \tau}$ .

$\displaystyle q(t) = \left(1 - \frac{1}{9}\right) \, q_0 = \frac{8}{9}\, q_0$ .

Apply the equation $\displaystyle q(t) = q_0 \, e^{-t / \tau}$ :

$\displaystyle \frac{8}{9}\, q_0 = q_0 \, e^{-t/\tau}$ .

The goal is to solve for $t$ in terms of $\tau$ . Rearrange the equation:

$\displaystyle e^{-t/\tau} = \frac{8}{9}$ .

Take the natural logarithm of both sides:

$\displaystyle \ln\, e^{-t/\tau} = \ln \frac{8}{9}$ .

$\displaystyle -\frac{t}{\tau} = \ln 8 - \ln 9$ .

$t = - \tau \, \left(\ln 8 - \ln 9\right) = \tau(\ln 9 - \ln 8)$ .

$\displaystyle q(t) = \left(1 - \frac{1}{9}\right) \, q_0 = \frac{7}{9}\, q_0$ .

Apply the equation $\displaystyle q(t) = q_0 \, e^{-t / \tau}$ :

$\displaystyle \frac{7}{9}\, q_0 = q_0 \, e^{-t/\tau}$ .

The goal is to solve for $t$ in terms of $\tau$ . Rearrange the equation:

$\displaystyle e^{-t/\tau} = \frac{7}{9}$ .

Take the natural logarithm of both sides:

$\displaystyle \ln\, e^{-t/\tau} = \ln \frac{7}{9}$ .

$\displaystyle -\frac{t}{\tau} = \ln 7 - \ln 9$ .

$t = - \tau \, \left(\ln 7 - \ln 9\right) = \tau(\ln 9 - \ln 7)$ .

7 0

3 years ago

2.4 What is the radiation error of a temperature measurement?<br>I

Airida [17]

Answer:

diameter of the wire = 0.05 in =0.05 /12 =4.167 *10 ^-3 ft

area of cross section of the wire = A = 22/7 * ( d /2 ) ^2 =0.786 * ( 4.167 *10 ^-3 ) ^2 =1.365 *10 ^-5 ft2

E =...

Explanation:

5 0

3 years ago

Question 1

solmaris [256]

Answer:

4.0 m/s²

Explanation:

Draw two free body diagrams, one for the cart and one for the hanging mass.

The cart has one force acting on it in the x direction: tension to the right.

The hanging mass has two forces acting on it in the y direction: tension up and weight down.

The hanging mass accelerates downward, so if we take up to be positive, then the acceleration is negative.

Apply Newton's second law to the hanging mass:

∑F = ma

T − m₂g = m₂(-a)

T − m₂g = -m₂a

Apply Newton's second law to the cart:

∑F = ma

T = m₁a

Substitute and solve for a:

m₁a − m₂g = -m₂a

m₁a + m₂a = m₂g

(m₁ + m₂) a = m₂g

a = m₂g / (m₁ + m₂)

Given m₁ = 2.3 kg and m₂ = 1.6 kg:

a = (1.6 kg × 9.8 m/s²) / (2.3 kg + 1.6 kg)

a = 4.0 m/s²

8 0

4 years ago

two people are pushing a box north across the floor. on person pushes with a force of 20n, the other person pushes with an unkno

REY [17]

It's 15 N because net force is total force so you take net force - known force = unknown force

3 0

3 years ago

Read 2 more answers