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Nadusha1986 [10]
3 years ago
7

Find the number of roots for the following equation. 9x5 + 12x4 – x2 + 8x + 4=0​

Mathematics
1 answer:
skad [1K]3 years ago
8 0

Answer:

5 roots

Step-by-step explanation:

Given

9x^5 + 12x^4 - x^2 + 8x + 4 = 0

Required

The number of roots

The degree of a polynomial represents the number of roots.

In the given equation, the degree of the polynomial is 5.

<em></em>

<em>Hence, the number of roots is 5</em>

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20

Step-by-step explanation:

Calculate 10% of total = 3 / 1.5 = 2

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2 x 10 = 20

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easy algebra question below first correct answer gets brainliest, if you put a link i will report and block
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Answer:

6x²

Step-by-step explanation:

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If the original square had a side length of
irina [24]

Answer:

Part a) The new rectangle labeled in the attached figure N 2

Part b) The diagram of the new rectangle with their areas  in the attached figure N 3, and the trinomial is x^{2} +11x+28

Part c) The area of the second rectangle is 54 in^2

Part d) see the explanation

Step-by-step explanation:

The complete question in the attached figure N 1

Part a) If the original square is shown below with side lengths marked with x, label the second diagram to represent the new rectangle constructed by increasing the sides as described above

we know that

The dimensions of the new rectangle will be

Length=(x+4)\ in

width=(x+7)\ in

The diagram of the new rectangle in the attached figure N 2

Part b) Label each portion of the second diagram with their areas in terms of x (when applicable) State the product of (x+4) and (x+7) as a trinomial

The diagram of the new rectangle with their areas  in the attached figure N 3

we have that

To find out the area of each portion, multiply its length by its width

A1=(x)(x)=x^{2}\ in^2

A2=(4)(x)=4x\ in^2

A3=(x)(7)=7x\ in^2

A4=(4)(7)=28\ in^2

The total area of the second rectangle is the sum of the four areas

A=A1+A2+A3+A4

State the product of (x+4) and (x+7) as a trinomial

(x+4)(x+7)=x^{2}+7x+4x+28=x^{2} +11x+28

Part c) If the original square had a side length of  x = 2 inches, then what is the area of the  second rectangle?

we know that

The area of the second rectangle is equal to

A=A1+A2+A3+A4

For x=2 in

substitute the value of x in the area of each portion

A1=(2)(2)=4\ in^2

A2=(4)(2)=8\ in^2

A3=(2)(7)=14\ in^2

A4=(4)(7)=28\ in^2

A=4+8+14+28

A=54\ in^2

Part d) Verify that the trinomial you found in Part b) has the same value as Part c) for x=2 in

We have that

The trinomial is

A(x)=x^{2} +11x+28

For x=2 in

substitute and solve for A(x)

A(2)=2^{2} +11(2)+28

A(2)=4 +22+28

A(2)=54\ in^2 ----> verified

therefore

The trinomial represent the total area of the second rectangle

7 0
3 years ago
Heather buys a dog bowl priced at $8. If the sales tax is 10%, how much tax will Heather<br> pay?
Fantom [35]

Answer:

I think the answer is 2 dollars

Step-by-step explanation:

4 0
3 years ago
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