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Lynna [10]
2 years ago
11

If the mass of a ball B is 1 kilogram and it’s speed is 1 m/sec. the mass and the speed of ball A is three times the mass and sp

eed of ball B. What is the ratio of kinetic energy of ball A to ball B? Hint: dividethe kinetic energy equation for ball A by the kinetic energy equation of ball B.
A.3
B.6
C.9
D.27
Physics
2 answers:
vichka [17]2 years ago
5 0

your answer would be 27.

vekshin12 years ago
4 0

The ratio of kinetic energy of ball A to ball B is 27

Answer: Option D

<u>Explanation: </u>

The kinetic energy of any object is the energy exhibited by the object when it is in motion. The kinetic energy of any object is directly proportional to the mass of the object and square of the speed at which the object is moving. So the kinetic energy of any object can be represented as

                 E_{k}=\frac{1}{2} \times m \times(\text { speed })^{2}

In this case, for ball B the mass is 1 kg and speed is 1 m/s. So the kinetic energy of ball B is

            \text { Kinetic energy for ball } B=\frac{1}{2} \times 1 \times 1^{2}=0.5 J

As it is said that the mass (M) and speed of ball A is three times the mass and speed of ball B.  So ,

         \text { M of ball } A=3 \times M \text { of ball } B=3 \times 1=3 \mathrm{kg}

And,

           \text { Speed of ball } A=3 \times \text { Speed of ball } B=3 \times 1=3 \mathrm{m} / \mathrm{s}

Thus, the kinetic energy of ball A will be

            \text {Kinetic energy for ball } A=\frac{1}{2} \times 3 \times 9=13.5 \mathrm{J}

Now, to determine the ratio of kinetic energy of ball A to ball B,

\text { Ratio of kinetic energy }=\frac{\text {Kinetic energy of Ball } A}{\text {Kinetic energy of Ball } B}=\frac{13.5}{0.5} = 27

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stepladder [879]

a) F=(3675i-4543k)N

b) 5843 N

Explanation:

a)

The position of the UFO at time t is given by the vector:

r(t)=(0.24t^3+25)i+(4.2t)j+(-0.43t^3+0.8t^2)k

Therefore it has 3 components:

r_x=0.24t^3+25\\r_y=4.2t\\r_z=-0.43t^3+0.8t^2

We start by finding the velocity of the UFO, which is given by the derivative of the position:

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The weight of the UFO is W = 12,500 N, so its mass is:

m=\frac{W}{g}=\frac{12500}{9.8}=1276 kg

Therefore, the components of the force on the UFO are given by Newton's second law:

F=ma

So, Substituting t = 2 s, we find:

F_x=ma_x=(1276)(1.44t)=(1276)(1.44)(2)=3675 N\\F_y=ma_y=0\\F_z=ma_z=(1276)(-2.58t+1.6)=(1276)(-2.58(2)+1.6)=-4543 N

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F=(3675i-4543k)N

b)

The magnitude of a 3-dimensional vector is given by

|v|=\sqrt{v_x^2+v_y^2+v_z^2}

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v_x,v_y,v_z are the three components of the vector

In this problem, the three components of the net force are:

F_x=3675 N\\F_y=0\\F_z=-4543 N

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|F|=\sqrt{3675^2+0^2+(-4543)^2}=5843 N

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Answer:

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