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1 year ago

in the bohr model, which energy transition will result in light being emitted with shortest wavelength?

Physics

1 answer:

RoseWind [281]1 year ago

7 0

The line of shortest wavelength is from n4 - n1.

<h3>What is bohr model ?</h3>

The Bohr model, also known as the Rutherford-Bohr model, was proposed by Niels Bohr and Ernest Rutherford in 1913 and depicts an atomic system with an orbiting system of electrons surrounding a small, dense nucleus. This arrangement is similar to that of the Solar System, except that electrostatic forces act as the forces of attraction rather than gravity.

The line with the shortest wavelength in the hydrogen spectrum is created when an electron in an atom of hydrogen transitions between the first and fourth energy levels (n4 →n1).

The transition n4→ n1 has the largest energy difference between the transitions that are given.

Lower wavelengths correspond to higher energy differences.

to learn more about bohr's model go to -

brainly.com/question/4138548

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Which best explains parallel forces?

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The answer is to this question is B

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3 years ago

What is the inverse square law and how does it relate to gravity?

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Answer:

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3 years ago

A thin Nichrome wire connected to an ammeter surrounds a region of time-varying magnetic flux, and the ammeter reads 13 amperes.

Semenov [28]

Answer:

The current would be same in both situation.

Explanation:

Given that,

Current I = 13 A

Number of turns = 23

We need to calculate the induced emf

Using formula of induced emf is

$\epsilon=NA\dfrac{dB}{dt}$

For N = 1

$\epsilon=A\dfrac{dB}{dt}$

We need to calculate the current

Using formula of current

$i=\dfrac{\epsilon}{R}$

Put the value of emf

$i=\dfrac{A\dfrac{dB}{dt}}{R}$

Now, if the number of turn is 22 , then induced emf would be

$\epsilon'=NA\dfrac{dB}{dt}$

Then the current would be

$i'=\dfrac{\epsilon'}{NR}$

$i'=\dfrac{NA\dfrac{dB}{dt}}{NR}$

$i'=\dfrac{A\dfrac{dB}{dt}}{R}$

$i'=i$

Hence, The current would be same in both situation.

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3 years ago

A convex mirror, like the passenger-side rearview mirror on a car, has a focal length of -3.0 m . An object is 6.0 m from the mi

Artist 52 [7]

A) -2.0 m

Look at the ray diagram attached in the picture, where:

p identifies the location of the object

q identifies the location of the image

F identifies the focus of the mirror

Each tick represents 1 m

We have

p = 6.0 m is the distance of the object from the mirror

f = -3.0 m is the focal length

From the ray diagram, we see that q has a distance of 2.0 m from the mirror, and it's on the other side of the mirror compared to the object, so

q = -2.0 m

This can also be verified by using the mirror equation:

$\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{-3.0 m}-\frac{1}{6.0 m}=-\frac{3}{6.0 cm}\\q = \frac{-6.0 cm}{3}=-2.0 cm$

B) Upright and virtual

As we see from the picture, the image is upright, since it has same orientation as the object.

Also, we notice that the image is on the other side of the mirror, compared to the object. For a mirror,

- An image is said to be real if it is on the same side of the object

- An image is said to be virtual if it is on the opposite side of the mirror

Therefore, this means that the image is virtual.

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2 years ago

A flashlight converts?

sammy [17]

Answer:

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1. Electrical energy into electromagnetic energy is the answer.

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2 years ago