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inessss [21]
3 years ago
13

NEED HELP! thank you!

Chemistry
1 answer:
Zanzabum3 years ago
7 0

Answer:

This is a physical change.

Explanation:

As long as the identity of the substance has not changed, and the element is present before and after, it is a physical change! (Ex: ice melting)

You might be interested in
The area surrounding the nucleus is called: protons electrons neutrons electron cloud
vesna_86 [32]

Answer:

eletrons

Explanation:

eletrons is not in the neuclus its around it

5 0
3 years ago
Read 2 more answers
Potassium hydroxide is classified as an arrhenius base because koh contains
mixas84 [53]

Answer: hydroxide ions

Explanation:

According to the Arrhenius concept, an acid is a substance that ionizes in the water to give hydronium ion or hydrogen ion  and a bases is a substance that ionizes in the water to give hydroxide ion .

According to the Bronsted Lowry conjugate acid-base theory, an acid is defined as a substance which donates protons and a base is defined as a substance which accepts protons.

According to the Lewis concept, an acid is defined as a substance that accepts electron pairs and base is defined as a substance which donates electron pairs.

As KOH can give hydroxide ions on dissociation , it is considered as arrhenius base.

KOH\rightarrow K^++OH^-

8 0
3 years ago
11. Fill in the blanks below for a general chemical reaction (products, reactants).
Bad White [126]
Reactants on the left and products on the right
5 0
3 years ago
What volume of a 0.232 M hydrobromic acid solution is required to neutralize 10.8 mL of a 0.162 M potassium hydroxide solution?
Naily [24]

Answer:

156 mL hydrobromic acid

Explanation:

3 0
3 years ago
3. What mass of copper could be deposited from a copper(II) Sulphate solution using a current of 5.0 A over 100 seconds? ( F =96
arsen [322]

Mass of copper : 0.165 g

<h3>Further explanation</h3>

Given

5.0 A over 100 seconds

Required

Mass of copper

Solution

Faraday's law:

<em>The mass of the substance formed at each electrode is proportional to the electric current flowing in the electrolysis</em>

<em />\tt W=\dfrac{e.i.t}{96500}<em />

e = Ar / valence = eqivalent weight

i = current

t = time

W = weight

CuSO₄ ----> Cu²⁺ + SO₄²⁻

Cu ----> Cu²⁺ + 2e

e = Ar/2

= 63,5/2 = 31,75

\tt W=\dfrac{31.75\times 5\times 100}{96500}=0.165~g

8 0
3 years ago
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