Answer:
The enthalpy of reaction for the reaction of chlorine with ozone is -162.5 kJ.
Explanation:
..[1]
..[2]
..[3]
The enthalpy of reaction for the reaction of chlorine with ozone can be calculated by using Hess's law:
[2] - [1] = [3]
The enthalpy of reaction for the reaction of chlorine with ozone is -162.5 kJ.
It also depends on what we use to make the energy in the power plants. Many use uranium which is non renewable. A better alternative would be wind or solar as it is always around. Hope this helps.
Answer:
The correct answer is A electron on the aniline nitrogen are somehow delocalized to the aromatic ring.
Explanation:
The structure of aniline contain double bonds and lone pair of electron in the nitrogen atom of -NH2 group that is attached to the benzene ring.
The electron pair present in the nitrogen atom of -NH3 group of aniline undergo delocalization with the aromatic ring of benzene resulting in the formation of resonance hybrid that increases the ability of nitrogen atom of -NH2 group of aniline to easily donate that lone pair of electron.
ON the other hand the resonance stabilization cannot be possible with the cyclohexylamine ring as it is saturated.
Your answer is
Ca(OH)₂ + 2HNO₃ → Ca(NO₃)₂ + 2H₂O I hope it is at least :P
<span>0.06355391 mol
The balanced equation for the reaction is
Na2B4O7*10H2O + 2 HNO3 = 2 NaNO3 + 4 H3BO3 + 5 H2O
So for each mole of Borax to neutralize, it takes 2 moles of HNO3.
Calculate number of moles of Borax
0.2619 g / 381.372 g/mol = 0.0006867 mol
Moles of HNO3 used = 0.0006867 mol * 2 = 0.0013734 mol
Molarity is defined as moles per liter so divide the number of moles used by the volume in liters. So
0.0013734 / 0.02161 = 0.06355391 mol</span>
