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blsea [12.9K]
3 years ago
15

Calculate the mass (in kg) of 245 cm3 of concrete if the density of concrete is 2400 kg/cm3. Give your answer to 2 decimal place

s
Enter your answer as a number
kg​
Physics
1 answer:
anyanavicka [17]3 years ago
4 0

Answer:

m= 245cm³×2400kg/cm³

=588000kg

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<span>ρwAd1g = Mg</span>

ρw<span>Ad2g = (M + m) g</span>

<span>d2∕d1 = (M + m)/g</span>

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How fast was the storm that hit Galveston and how men died?​
vodomira [7]

Answer:

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Which of these are minerals? Select all that apply
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From that particular list:

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3 years ago
A mass of 1000 kg drops from a height of 10 m on a platform of negligible mass. It is desired to design a spring and dashpot on
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Answer:

k = 5\times 10^{4}\ N/m

b = 0.707\times 10^{3}

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Solution:

As per the question:

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Height, h = 10 m

Equilibrium position, x = 0.2 m

Now,

The velocity when the mass falls from a height of 10 m is given by the third eqn of motion:

v^{2} = u^{2} + 2gh

where

u = initial velocity = 0

g = 10m/s^{2}

Thus

v = \sqrt{2\times 10\times 10} = 10\sqrt{2}\ m/s

Force on the mass is given by:

F = mg = 1000\times 10 = 10000 N = 10\ kN

Also, we know that the spring force is given by:

F = - kx

Thus

k = \frac{F}{x} = \frac{10000}{0.2} = 5\times 10^{4}\ N/m

Now, to find the damping constant b, we know that:

F = - bv

b = \frac{F}{v} = \frac{10000}{10\sqrt{2}} = 0.707\times 10^{3}

Now,

Time required for the platform to get settled to 1 mm or 0.001 m is given by:

t = \frac{0.001}{v} = \frac{0.001}{10\sqrt{2}} = 7.1\times 10^{- 5}\ s

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3 years ago
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Answer:

Both forces act along the line joining the objects like masses or charges. And both forces are inversely proportional to the square of the distance between the objects, this is known as the inverse-square law.

Explanation:

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