Answer:
n = 1.42
Explanation:
The refractive index for a medium is given by the ratio of the speed of light in vacuum to the speed of light in a medium.

So, the refractive index of the medium is 1.42.
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32,100 Millimeters
3,210 Centimeters
3.21 Decameters
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The final temperature of the system will be equal to the initial temperature, and which is 373K. The work done by the system is 409.8R Joules.
To find the answer, we need to know about the thermodynamic processes.
<h3>How to find the final temperature of the gas?</h3>
- Any processes which produce change in the thermodynamic coordinates of a system is called thermodynamic processes.
- In the question, it is given that, the tank is rigid and non-conducting, thus, dQ=0.
- The membrane is raptured without applying any external force, thus, dW=0.
- We have the first law of thermodynamic expression as,

,

- Thus, the final temperature of the system will be equal to the initial temperature,

<h3>How much work is done?</h3>
- We found that the process is isothermal,
- Thus, the work done will be,

Where, R is the universal gas constant.
<h3>What is a reversible process?</h3>
- Any process which can be made to proceed in the reverse direction is called reversible process.
- During which, the system passes through exactly the same states as in the direct process.
Thus, we can conclude that, the final temperature of the system will be equal to the initial temperature, and which is 373K. The work done by the system is 409.8R Joules.
Learn more about thermodynamic processes here:
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Answer:
f = 409 Hz
Explanation:
We have,
Length of the open organ pipe, l = 0.29 m
Frequency of vibration of second overtone, 
It is required to find the fundamental frequency of the pipe. For the open organ pipe, the frequency of second overtone is given by :

v is speed of sound
Let f is the fundamental frequency. It is given by :

The relation between f and f₂ can be written as :

So, the fundamental frequency of the pipe is 409 Hz.